{"id":1188,"date":"2023-11-16T04:55:27","date_gmt":"2023-11-15T23:25:27","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=1188"},"modified":"2023-11-17T14:19:11","modified_gmt":"2023-11-17T08:49:11","slug":"samacheer-kalvi-7th-maths-term-1-chapter-5-ex-5-1","status":"publish","type":"post","link":"https:\/\/samacheerguru.com\/samacheer-kalvi-7th-maths-term-1-chapter-5-ex-5-1\/","title":{"rendered":"Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 5 Geometry Ex 5.1"},"content":{"rendered":"

Students can Download Maths Chapter 5 Geometry Ex 5.1 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions<\/a> Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.<\/p>\n

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 5 Geometry Ex 5.1<\/h2>\n

Question 1.
\nName the pairs of adjacent angles.
\nSolution:
\n(i) \u2220ABG and \u2220GBC are adjacent angles.
\n(ii) \u2220BCF and \u2220FCD are adjacent angles.
\n(iii) \u2220BCF and \u2220FCE are adjacent angles.
\n(iv) \u2220FCE and \u2220ECD are adjacent angles.
\n\"Samacheer<\/p>\n

Question 2.
\nFind the angle \u2220JIL from the given figure.
\nSolution:
\n\u2220LIK and \u2220KIJ are adjacent angles.
\n\u2234 \u2220JIL = \u2220LIK + \u2220KIJ
\n= 38\u00b0 + 27\u00b0
\n= 65\u00b0
\n\u2234 \u2220JIL = 65\u00b0
\n\"Samacheer<\/p>\n

Question 3.
\nFind the angles \u2220GEH from the given figure.
\nSolution:
\n\"Samacheer
\n\u2220HEF = \u2220HEG + \u2220GEF
\n120\u00b0 = \u2220HEG + 34\u00b0
\n120\u00b0- 34\u00b0 = \u2220GEH + 34\u00b0 – 34\u00b0
\n\u2220GEH = 86\u00b0<\/p>\n

Question 4.
\nGiven that AB is a straight line. Calculate the value of x\u00b0 in the following cases.
\n\"Samacheer
\nSolution:
\n(i) Since the angles are linear pair \u2220AOC + \u2220BOC = 180\u00b0
\n72\u00b0 + x\u00b0 = 180\u00b0
\n72\u00b0 + x\u00b0 – 12\u00b0 = 180\u00b0- 72\u00b0
\nx\u00b0 = 108\u00b0<\/p>\n

(ii) Since the angles are linear pair
\n\u2220AOC + \u2220BOC = 180\u00b0
\n3x + 42\u00b0 = 180\u00b0
\n\"Samacheer<\/p>\n

(iii) Since the angles are linear pair
\n\u2220AOC + \u2220BOC = 180\u00b0
\n4x\u00b0 + 2x\u00b0 = 180\u00b0
\n6x\u00b0 = 180\u00b0
\nx\u00b0 = 180\u00b0<\/p>\n

Question 5.
\nOne angle of a linear pair is a right angle. What can you say about the other angle?
\nSolution:
\nIf the angle are linear pair, then their sum is 180\u00b0.
\nGiven one angle is right angle ie 90\u00b0.
\n\u2234 The other angle = 180\u00b0 -90\u00b0 = 90\u00b0
\n\u2234 The other angle also a right angle<\/p>\n

Question 6.
\nIf the three angles at a point are in the ratio 1 : 4 : 7, find the value of each angle?
\nSolution:
\nWe know that the sum of angles at a point is 360\u00b0.
\nGiven the three angles are in the ratio 1:4:7.
\nLet the three angles be 1x, 4x, 7x.
\n\"Samacheer
\n\u2234 The three angles are 30\u00b0, 120\u00b0 and 210\u00b0.<\/p>\n

Question 7.
\nThree are six angles at a point. One of them is 45\u00b0 and the other five angles are all equal. What is the measure of all the five angles.
\nSolution:
\nWe know that the sum of angles at a point is 360\u00b0.
\nOne angle = 45\u00b0
\nLet the equal angles be x\u00b0 each
\n\u2234 x\u00b0 + x\u00b0 + x\u00b0 + x\u00b0 + x\u00b0 + 45\u00b0 = 360\u00b0
\n5x\u00b0 + 45\u00b0 – 45\u00b0 = 360\u00b0 – 45\u00b0
\n\"Samacheer
\n5x\u00b0 = 315\u00b0
\n\"Samacheer
\n\u2234 Measure of all 5 equal angles = 63\u00b0.<\/p>\n

Question 8.
\nIn the given figure, identify
\n(i) Any two pairs of adjacent angles.
\n(ii) Two pairs of vertically opposite angles.
\nSolution:
\n(i) (a) \u2220PQT and \u2220TOS are adjacent angles.
\n(b) \u2220PQU and \u2220UQR are adjacent angles.
\n(ii) (a) \u2220PQT and \u2220RQU are vertically opposite angles.
\n(b) \u2220TQR and \u2220PQU are vertically opposite angles.<\/p>\n

Question 9.
\nThe angles at a point are x\u00b0, 2x\u00b0, 3x\u00b0, 4x\u00b0 and 5x\u00b0. Find the value of the largest angle?
\nSum of angles at a point = 360\u00b0
\n\u2234 x\u00b0 + 2x\u00b0 + 3x\u00b0 + 4x\u00b0 + 5x\u00b0 = 360\u00b0
\n15x\u00b0 = 360\u00b0
\nx\u00b0 = \\(\\frac{360^{\\circ}}{15}\\)
\nx\u00b0 = 24\u00b0.
\n\u2234 The largest angle = 5x\u00b0
\n= 5 \u00d7 24\u00b0 = 120\u00b0
\nThe largest angle is 120\u00b0<\/p>\n

Question 10.
\nFrom the given figure, find the missing angle.
\nSolution:
\nLines \\(\\overleftrightarrow { RP }\\) and \\(\\overleftrightarrow { SQ }\\) are interesting at \u2018O\u2019
\n\"Samacheer
\n\u2234 Vertically opposite angles are equal.
\n\u2234 x = 105\u00b0
\n\u2234 Missing angle = 105\u00b0<\/p>\n

Question 11.
\nFind the angles x\u00b0 and y\u00b0 in the figure shown.
\n\"Samacheer
\nSolution:
\nConsider the line m.
\nx\u00b0 and 3x\u00b0 are linear pair of angles
\n\u2234 x\u00b0 + 3x\u00b0 = 180\u00b0
\n\"Samacheer
\n\"Samacheer
\nx\u00b0 = 45\u00b0
\nAlso lines l and m intersects.
\nVertically opposite angles are equal.
\nie 3x\u00b0 = y\u00b0
\n3 \u00d7 45\u00b0 = y\u00b0
\ny = 135\u00b0
\nx\u00b0 = 15\u00b0 and
\ny\u00b0 = 135\u00b0<\/p>\n

Question 12.
\nUsing the figure, answer the following questions.
\n\"Samacheer
\n(i) What is the measure of angle x\u00b0?
\n(ii) What is the measure of angle y\u00b0?
\nSolution:
\nFrom the figure x\u00b0 and 125\u00b0 are vertically opposite angles. So they are equal ie
\nie x\u00b0 = 125\u00b0
\nAlso y\u00b0 and 125\u00b0 are linear pair of angles.
\n\u2234 y\u00b0 + 125\u00b0 = 180\u00b0
\ny\u00b0 + 125\u00b0 – 125\u00b0 = 180\u00b0- 125\u00b0
\ny\u00b0 = 55\u00b0
\nx\u00b0 = 125\u00b0,
\ny\u00b0 = 55\u00b0<\/p>\n

Question 13.
\nAdjective angles have
\n(i) No common interior, no common arm, no common vertex.
\n(ii) One common vertex, one common arm, common interior
\n(iii) One common arm, one common vertex, no common interior.
\n(iv) One common arm, no common vertex, no common interior.
\nSolution:
\n(iii) one common arm, one common vertex, no common interior<\/p>\n

Question 14.
\nIn the given figure the angles \u22201 and \u22202 are
\n(i) Opposite angles
\n(ii) Adjacent angles
\n(iii) Linear angles
\n(iv) Supplementary angles
\n\"Samacheer
\nSolution:
\n(iii) Linear pair<\/p>\n

Question 15.
\nVertically opposite angles are
\n(i) not equal in measure
\n(ii) Complementary
\n(iii) supplementary
\n(iv) equal in measure
\nSolution:
\n(iv) equal in measure<\/p>\n

Question 16.
\nThe sum of all angles at a point is
\n(i) 360\u00b0
\n(ii) 180\u00b0
\n(iii) 90\u00b0
\n(iv) 0\u00b0
\nSolution:
\n(i) 360\u00b0<\/p>\n

Question 17.
\nThe measure of \u2220BOC is
\n(i) 90\u00b0
\n(ii) 180\u00b0
\n(iii) 80\u00b0
\n(iv) 100\u00b0
\n\"Samacheer
\nSolution:
\n(iii) 80\u00b0<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Maths Chapter 5 Geometry Ex 5.1 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations. Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 1 Chapter 5 Geometry Ex 5.1 Question 1. […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[5],"tags":[],"blocksy_meta":"","jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/1188"}],"collection":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/comments?post=1188"}],"version-history":[{"count":1,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/1188\/revisions"}],"predecessor-version":[{"id":55054,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/1188\/revisions\/55054"}],"wp:attachment":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/media?parent=1188"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/categories?post=1188"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/tags?post=1188"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}