{"id":3287,"date":"2023-12-07T11:56:45","date_gmt":"2023-12-07T06:26:45","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=3287"},"modified":"2023-12-08T17:55:01","modified_gmt":"2023-12-08T12:25:01","slug":"samacheer-kalvi-8th-maths-solutions-term-2-chapter-1-additional-questions","status":"publish","type":"post","link":"https:\/\/samacheerguru.com\/samacheer-kalvi-8th-maths-solutions-term-2-chapter-1-additional-questions\/","title":{"rendered":"Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 1 Life Mathematics Additional Questions"},"content":{"rendered":"

Students can Download Maths Chapter 1 Life Mathematics Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions<\/a> Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.<\/p>\n

Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 1 Life Mathematics Additional Questions<\/h2>\n

Additional Questions and Answers<\/span><\/p>\n

Question 1.
\nFill in the blanks<\/p>\n

Question (a)
\nPercent means ……….
\nAnswer:
\nPer hundred or out of hundred.<\/p>\n

Question (b)
\nPercent is useful in ………
\nAnswer:
\nComparing quantities easily<\/p>\n

\"Samacheer<\/p>\n

Question (c)
\nThe formula to find the increased quantity ………
\nAnswer:
\nI = (1 + \\(\\frac{x}{100}\\))<\/p>\n

Question (d)
\nThe formula to find the decreased quantity ………
\nAnswer:
\nD = (1 + \\(\\frac{x}{100}\\))<\/p>\n

Question (e)
\nGain or profit % ……..
\nAnswer:
\n(\\(\\frac{Profit}{C.P}\\) x 100)%<\/p>\n

Question (f)
\nLoss % = ………..
\nAnswer:
\n(\\(\\frac{Loss}{C.P}\\) x 100)%<\/p>\n

Question (g)
\nS.P = ………. (if gain % is given)
\nAnswer:
\n\"Samacheer<\/p>\n

Question (h)
\nC.P = ……… (if gain % is given)
\nAnswer:
\n\"Samacheer<\/p>\n

Question (f)
\nS.P = ………. (if loss % is given)
\nAnswer:
\n\"Samacheer<\/p>\n

Question (h)
\nC.P = ………. (if loss % is given)
\nAnswer:
\n\"Samacheer<\/p>\n

Question (k)
\nSelling price = Marked price – …………
\nAnswer:
\nDiscount<\/p>\n

\"Samacheer<\/p>\n

Question (l)
\nCost price = Cost price + ……….
\nAnswer:
\nOver head expenses<\/p>\n

Question 2.
\nIf y% of \u20b9 1000 is 600, find the value ofy.
\nSolution:
\ny% of 1000 = 600
\n\\(\\frac{y}{100}\\) x 1000 = 600
\ny = \\(\\frac{600}{10}\\)
\ny = 60<\/p>\n

Question 3.
\nA number when decreased by 10% becomes 900. Then find the number.
\nSolution:
\nLet the number be \u2018x\u2019
\nGiven x – \\(\\frac{10}{100}\\)x = 900
\n\\(\\frac{100x-10x}{100}\\) = 900
\n\\(\\frac{90x}{100}\\) = 900
\nx = \\(\\frac{900×100}{90}\\) = 1000<\/p>\n

Question 4.
\nIf the population in a city has increased from 5,00,000 to 7,00,000 in a year, find the percentage increase in population.
\nSolution:
\nIncrease in population = 7,00,000 – 5,00,000 = 2,00,000
\nPercentage increase in population = \\(\\frac{2,00,000}{5,00,000}\\) x 100 = 40%<\/p>\n

\"Samacheer<\/p>\n

Question 5.
\nIf the selling price of a refrigerator is equal to \\(\\frac{10}{8}\\) of its cost price, then find the gain\/ profit percent.
\nSolution:
\nLet the C.P of the refrigerator be x
\nS.P = \\(\\frac{10}{8}\\)x
\nProfit = S.P – C.P = \\(\\frac{10}{8}\\)x – x = \\(\\frac{10x-8x}{8}\\) = \\(\\frac{2x}{8}\\)
\n\"Samacheer<\/p>\n

Question 6.
\nKarnan bought a dishwasher for \u20b9 32,300 and paid \u20b9 2700 for its transportation. Then he sold it for X 38,500. Find his gain or loss percent.
\nSolution:
\nTotal C.P of the dishwasher = C.P + Overhead expenses.
\n= \u20b9 32300 + \u20b9 2700 = \u20b9 35000
\nS.P = \u20b9 38500
\nTherefore, we find S.P > C.P
\n\"Samacheer<\/p>\n

Question 7.
\nThe value of a car 2 years ago was \u20b9 1,40,000. It depreciates at the rate of 4% p.a. Find its present value.
\nSolution:
\nDepreciated value = P(1 + \\(\\frac{r}{100}\\))n<\/sup> = 1,40,000(1 – \\(\\frac{4}{100}\\))2<\/sup>
\n= 1,40,000(\\(\\frac{96}{100}\\)) x (\\(\\frac{96}{100}\\)) = \u20b9 1,29,024<\/p>\n

\"Samacheer<\/p>\n

Question 8.
\nFind the difference in C.I and S.I for P = \u20b9 10,000, r = 4% p.a, n = 2 years.
\nSolution:
\nC.I – S.I = P(\\(\\frac{r}{100}\\))2<\/sup> = 10,000(\\(\\frac{4}{100}\\))2<\/sup>
\n= 10,000 x \\(\\frac{4}{100}\\) x \\(\\frac{4}{100}\\) = \u20b9 16<\/p>\n

Question 9.
\nFind the C.I for the given Principal = \u20b9 8,000, r = 5% p.a, n = 2 years
\nAmount A = P(1 + \\(\\frac{r}{100}\\))n<\/sup> = 8000(1 + \\(\\frac{5}{100}\\))2<\/sup>
\n= 8000 x \\(\\frac{105}{100}\\) x \\(\\frac{105}{100}\\)
\n= 8000 x \\(\\frac{21}{20}\\) x \\(\\frac{21}{20}\\)
\nA = \u20b9 8820
\nCl = A – P = 8820 – 8000 = 820<\/p>\n

Question 10.
\nFind the S.I for the principal P = \u20b9 16,000, r = 5% p.a, n = 3 years
\nSolution:
\nP = \u20b9 16,000, n= 3 years, r = 5%
\nS.I = \\(\\frac{Pnr}{100}\\) = \\(\\frac{16000x3x5}{100}\\) = \u20b9 2400<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Maths Chapter 1 Life Mathematics Additional Questions and Answers, Notes Pdf, Samacheer Kalvi 8th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations. Samacheer Kalvi 8th Maths Solutions Term 2 Chapter 1 Life Mathematics Additional Questions Additional Questions […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[4],"tags":[],"blocksy_meta":"","jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/3287"}],"collection":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/comments?post=3287"}],"version-history":[{"count":1,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/3287\/revisions"}],"predecessor-version":[{"id":55204,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/3287\/revisions\/55204"}],"wp:attachment":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/media?parent=3287"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/categories?post=3287"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/tags?post=3287"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}