{"id":4048,"date":"2023-12-19T07:04:25","date_gmt":"2023-12-19T01:34:25","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=4048"},"modified":"2023-12-19T17:28:20","modified_gmt":"2023-12-19T11:58:20","slug":"samacheer-kalvi-7th-maths-term-2-chapter-4-intext-questions","status":"publish","type":"post","link":"https:\/\/samacheerguru.com\/samacheer-kalvi-7th-maths-term-2-chapter-4-intext-questions\/","title":{"rendered":"Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 4 Geometry Intext Questions"},"content":{"rendered":"

Students can Download Maths Chapter 4 Geometry Intext Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions<\/a> Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.<\/p>\n

Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 4 Geometry Intext Questions<\/h2>\n

Exercise 4.1<\/span><\/p>\n

Try These (Text book Page No. 66)<\/span><\/p>\n

Answer the following questions.<\/p>\n

Question 1.
\nTriangle is formed by joining three ______ points.
\nAnswer::
\nNon collinear<\/p>\n

Question 2.
\nA triangle has ______ vertices and ______ sides.
\nAnswer:
\nthree, three<\/p>\n

Question 3.
\nA point where two sides of a triangle meet is known as ______ of a triangle.
\nAnswer:
\nvertese<\/p>\n

\"Samacheer<\/p>\n

Question 4.
\nEach angle of an equilateral triangle is of measure.
\nAnswer:
\nsame<\/p>\n

Question 5.
\nA triangle has angle measurements of 29\u00b0, 65\u00b0 and 86\u00b0. Then it is ______ triangle.
\n(i) an acute angled
\n(ii) a right angled
\n(iii) an obtuse angled
\n(iv) a scalene
\nAnswer:
\n(i) an acute angled<\/p>\n

Question 6.
\nA triangle has angle measurements of 30\u00b0, 30\u00b0 and 120\u00b0. Then it is ______ triangle.
\n(i) an acute angled
\n(ii) scalene
\n(iii) obtuse angled
\n(iv) right angled
\nAnswer:
\nobtuse angled<\/p>\n

\"Samacheer<\/p>\n

Question 7.
\nWhich of the following can be the sides of a triangle?
\n(i) 5.9.14
\n(ii) 7,7,15
\n(iii) 1,2,4
\n(iv) 3, 6, 8
\nAnswer:
\n(iv) 3, 6, 8
\nSolution:
\n(i) Here 5 + 9 = 14 = the measure of the third side.
\nIn a triangle the sum of the measures of any two sides must be greater than the third side.
\n\u2234 5, 9, 14 cannot be the sides of a triangle.<\/p>\n

(ii) 7.7.15
\nHere sum of two sides 7 + 7 = 14 < the measures of the thrid side.
\nSo 1,1, 15 cannot be the sides of a triangles.<\/p>\n

(iii) 1,2,4
\nHere sum of two sides 1 + 2 = 3 < the measure of the third side.
\n\u2234 1, 2, 4 cannot be the sides of a triangle.<\/p>\n

(iv) 3, 6, 8
\nSum of two sides 3 + 6 = 9 > the third side.
\n\u2234 3, 6, 8 can be the sides of a triangle.<\/p>\n

\"Samacheer<\/p>\n

Question 8.
\nEzhil wants to fence his triangular garden. If two of the sides measure 8 feet and 14 feet then the length of the third side is ______
\n(i) 11 ft
\n(ii) 6 ft
\n(iii) 5 ft
\n(iv) 22 ft
\nAnswer:
\n(i) 11 ft<\/p>\n

Question 9.
\nCan we have more than one right angle in a triangle?
\nSolution:
\nNo, we cannot have more than one right angle in a triangle.
\nBecause the sum of three angles of a triangle is 180\u00b0.
\nBut if two angles are right angles then their sum itself become 180\u00b0.<\/p>\n

\"Samacheer<\/p>\n

Question 10.
\nHow many obtuse angles are possible in a triangle?
\nSolution:
\nOnly one.<\/p>\n

Question 11.
\nIn a right triangle, what will be the sum of other two angles?
\nSolution:
\nSum of three angles of a triangle = 180\u00b0
\nIf one angle is right angle (i.e. 90\u00b0) .
\nSum of other two sides = 180\u00b0 – 90\u00b0 = 90\u00b0<\/p>\n

Question 12.
\nIs it possible to form an isosceles right angled triangle? Explain.
\nSolution:
\nYes, it is possible.
\nIf one angle is right angle, then the other two angles will be 45\u00b0 and 45\u00b0.<\/p>\n

\"Samacheer<\/p>\n

Exercise 4.2<\/span><\/p>\n

Try These (Text book Page No. 76)<\/span><\/p>\n

Question 1.
\nMeasure and group the pair of congruent line segments.
\n\"Samacheer
\nSolution:
\n\\(\\overline{A B}\\) = 3 cm
\n\\(\\overline{C D}\\) = 4.8 cm
\n\\(\\overline{I J}\\) = 4.8 cm
\n\\(\\overline{P Q}\\) = 3 cm
\n\\(\\overline{R S}\\) = 1.7 cm
\n\\(\\overline{X Y}\\) = 1.7 cm
\nFrom the above measurement S, we can conclude that
\n(i) \\(\\overline{A B}\\) \u2245 \\(\\overline{P Q}\\)
\n(ii) \\(\\overline{C D}\\) \u2245 \\(\\overline{I J}\\)
\n(iii) \\(\\overline{R S}\\) \u2245 \\(\\overline{X Y}\\)<\/p>\n

\"Samacheer<\/p>\n

Try These (Text book Page No. 77)<\/span><\/p>\n

Question 1.
\nFind the pairs of congruent angles either by superposition method or by measuring them.
\n\"Samacheer
\nSolution:
\nFrom the given figures
\n\u2220ABC = 50\u00b0
\n\u2220EFG = 120\u00b0
\n\u2220HIJ = 120\u00b0
\n\u2220KLH = 90\u00b0
\n\u2220PON = 50\u00b0
\n\u2220RST = 90\u00b0
\nFrom the above measures, we can conclude that
\n(i) \u2220ABC = \u2220PON
\n(ii) \u2220EFG = \u2220HIJ
\n(iii) \u2220KLH \u2245 \u2220RST<\/p>\n

Try These (Text book Page No. 83)<\/span><\/p>\n

Question 1.
\nIf \u2206ABC \u2245 \u2206XYZ then list the corresponding sides and corresponding angles.
\n\"Samacheer
\nSolution:
\nIf \u2206ABC \u2245 \u2206XYZ
\n\\(\\overline{A B}\\) \u2245 \\(\\overline{X Y}\\) – \\(\\overline{B C}\\) \u2245 \\(\\overline{Y Z}\\)
\n\\(\\overline{A C}\\) \u2245 \\(\\overline{X Z}\\)
\nAnd also
\n\u2220A \u2245 \u2220X – \u2220B \u2245 \u2220Y
\n\u2220C \u2245 \u2220Z<\/p>\n

\"Samacheer<\/p>\n

Question 2.
\nGiven triangles are congruent. Identify the corresponding parts and write the congruent statement.
\n\"Samacheer
\nSolution:
\nGiven the set of triangles are congruent. Also we observe from the triangles that the corresponding sides.
\n\\(\\overline{A B}\\) = \\(\\overline{A C}\\)
\n\\(\\overline{B C}\\) = \\(\\overline{Y Z}\\)
\n\\(\\overline{A C}\\) = \\(\\overline{X Z}\\)
\nHere three sides of \u2206ABC are equal to the corresponding sides of \u2206XYZ.
\nThis criterion of congruency is side – side – side.<\/p>\n

Question 3.
\nMention the conditions needed to conclude the congruency of the triangles with reference to the above said criterions. Give reasons for your answer.
\n\"Samacheer
\nSolution:
\n(i) In \u2206ABC and \u2206XYZ
\nif \\(\\overline{A B}\\) = \\(\\overline{X Y}\\)
\n\\(\\overline{B C}\\) = \\(\\overline{Y Z}\\)
\n\\(\\overline{A C}\\) = \\(\\overline{X Z}\\)
\nthen \u2206ABC \u2245 \u2206XYZ. By the Side – Side -Side Congruency Criterion.<\/p>\n

\"Samacheer
\nthen \u2206AB \u2245 \u2206XYZ.
\nBy Side – Angle – Side Criterion.<\/p>\n

\"Samacheer
\nthen \u2206ABC \u2245 \u2206XYZ.
\nBy Angle – Side – Angle Congruency Critirion.<\/p>\n

\"Samacheer
\nthen by RHS criterion.
\n\u2206ABC \u2245 \u2206XYZ<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Maths Chapter 4 Geometry Intext Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations. Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 4 Geometry Intext Questions Exercise 4.1 Try […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[5],"tags":[],"blocksy_meta":"","jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/4048"}],"collection":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/comments?post=4048"}],"version-history":[{"count":1,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/4048\/revisions"}],"predecessor-version":[{"id":55279,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/4048\/revisions\/55279"}],"wp:attachment":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/media?parent=4048"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/categories?post=4048"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/tags?post=4048"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}