{"id":50209,"date":"2021-05-24T18:18:51","date_gmt":"2021-05-24T12:48:51","guid":{"rendered":"https:\/\/samacheerguru.com\/?p=50209"},"modified":"2021-05-29T18:04:21","modified_gmt":"2021-05-29T12:34:21","slug":"samacheer-kalvi-11th-maths-guide-chapter-3-ex-3-1-in-tamil","status":"publish","type":"post","link":"https:\/\/samacheerguru.com\/samacheer-kalvi-11th-maths-guide-chapter-3-ex-3-1-in-tamil\/","title":{"rendered":"Samacheer Kalvi 11th Maths Guide Chapter 3 \u0b85\u0b9f\u0bbf\u0baa\u0bcd\u0baa\u0b9f\u0bc8 \u0b87\u0baf\u0bb1\u0bcd\u0b95\u0ba3\u0bbf\u0ba4\u0bae\u0bcd Ex 3.1"},"content":{"rendered":"

Tamilnadu State Board New Syllabus Samacheer Kalvi 11th Maths Guide<\/a> Pdf Chapter 3 \u0b85\u0b9f\u0bbf\u0baa\u0bcd\u0baa\u0b9f\u0bc8 \u0b87\u0baf\u0bb1\u0bcd\u0b95\u0ba3\u0bbf\u0ba4\u0bae\u0bcd Ex 3.1 Textbook Questions and Answers, Notes.<\/p>\n

TN Board 11th Maths Solutions Chapter 3 \u0b85\u0b9f\u0bbf\u0baa\u0bcd\u0baa\u0b9f\u0bc8 \u0b87\u0baf\u0bb1\u0bcd\u0b95\u0ba3\u0bbf\u0ba4\u0bae\u0bcd Ex 3.1<\/h2>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 1.
\n\u0b95\u0bca\u0b9f\u0bc1\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f \u0b95\u0bcb\u0ba3\u0b99\u0bcd\u0b95\u0bb3\u0bcd \u0b8e\u0ba8\u0bcd\u0ba4\u0b95\u0bcd \u0b95\u0bbe\u0bb1\u0bcd\u0baa\u0b95\u0bc1\u0ba4\u0bbf\u0baf\u0bbf\u0bb2\u0bcd \u0b85\u0bae\u0bc8\u0baf\u0bc1\u0bae\u0bcd \u0b8e\u0ba9\u0bcd\u0baa\u0ba4\u0bc8\u0b95\u0bcd \u0b95\u0bbe\u0ba3\u0bcd\u0b95.
\n(i) 25\u00b0
\n(ii) 825\u00b0
\n(iii) -55\u00b0
\n(iv) 328\u00b0
\n(v) -230\u00b0
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n(i) 25\u00b0 = \u0bae\u0bc1\u0ba4\u0bb2\u0bcd \u0b95\u0bbe\u0bb1\u0bcd\u0baa\u0b95\u0bc1\u0ba4\u0bbf\u0baf\u0bbf\u0bb2\u0bcd \u0b85\u0bae\u0bc8\u0baf\u0bc1\u0bae\u0bcd.
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

(ii) 825\u00b0
\n825\u00b0 = 2 \u00d7 360\u00b0 + 105\u00b0 = (2 \u00d7 360\u00b0) + (90\u00b0+ 15\u00b0)= \u0b87\u0bb0\u0ba3\u0bcd\u0b9f\u0bbe\u0bae\u0bcd \u0b95\u0bbe\u0bb1\u0bcd\u0baa\u0b95\u0bc1\u0ba4\u0bbf\u0baf\u0bbf\u0bb2\u0bcd \u0b85\u0bae\u0bc8\u0baf\u0bc1\u0bae\u0bcd.
\n\"Samacheer<\/p>\n

(iii) – 55\u00b0 = \u0ba8\u0bbe\u0ba9\u0bcd\u0b95\u0bbe\u0bae\u0bcd \u0b95\u0bbe\u0bb1\u0bcd\u0baa\u0b95\u0bc1\u0ba4\u0bbf\u0baf\u0bbf\u0bb2\u0bcd \u0b85\u0bae\u0bc8\u0baf\u0bc1\u0bae\u0bcd.
\n\"Samacheer<\/p>\n

(iv) 328\u00b0
\n328\u00b0 = 270\u00b0 + 58\u00b0 = \u0ba8\u0bbe\u0ba9\u0bcd\u0b95\u0bbe\u0bae\u0bcd \u0b95\u0bbe\u0bb1\u0bcd\u0baa\u0b95\u0bc1\u0bae\u0bcd \u0b85\u0bae\u0bc8\u0baf\u0bc1\u0bae\u0bcd.
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

(v) -230\u00b0
\n-230\u00b0 = -180\u00b0 + (-50\u00b0) = \u0b87\u0bb0\u0ba3\u0bcd \u0b95\u0bbe\u0bb1\u0bcd\u0baa\u0b95\u0bc1\u0ba4\u0bbf\u0baf\u0bbf\u0bb2\u0bcd \u0b85\u0bae\u0bc8\u0baf\u0bc1\u0bae\u0bcd.
\n\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 2.
\n0 \u2264 \u03b8 \u2264 360\u00b0-\u0bb2\u0bcd \u0b95\u0bca\u0b9f\u0bc1\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f \u0b92\u0bb5\u0bcd\u0bb5\u0bca\u0bb0\u0bc1
\n\u0b95\u0bcb\u0ba3\u0ba4\u0bcd\u0ba4\u0bbf\u0bb1\u0bcd\u0b95\u0bbe\u0ba9 \u0b87\u0ba3\u0bc8 \u0bae\u0bc1\u0ba9\u0bc8\u0baf\u0b95\u0bcd \u0b95\u0bcb\u0ba3\u0ba4\u0bcd\u0ba4\u0bc8 \u0b95\u0bbe\u0ba3\u0bcd\u0b95.
\n(i) 395\u00b0
\n(ii) 525\u00b0
\n(iii) 1150\u00b0
\n(iv) -270\u00b0
\n(V) -450
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n(i) 395\u00b0 = 360\u00b0 + 350
\n\u21d2 395\u00b0 – 35\u00b0 = 360\u00b0
\n\u2234 395\u00b0-\u0b95\u0bcd\u0b95\u0bbe\u0ba9 \u0b87\u0ba3\u0bc8 \u0bae\u0bc1\u0ba9\u0bc8\u0baf\u0b95\u0bcd \u0b95\u0bcb\u0ba3\u0bae\u0bcd = 35\u00b0<\/p>\n

(ii) 525
\n525 = 360\u00b0 + 165\u00b0
\n\u21d2 525\u00b0 – 165\u00b0 = 360\u00b0
\n\u2234 525\u00b0-\u0b95\u0bcd\u0b95\u0bbe\u0ba9 \u0b87\u0ba3\u0bc8 \u0bae\u0bc1\u0ba9\u0bc8\u0baf\u0b95\u0bcd \u0b95\u0bcb\u0ba3\u0bae\u0bcd = 165\u00b0<\/p>\n

(iii)1150\u00b0
\n\u21d2 1150\u00b0 = 360\u00b0 + 360\u00b0 + 360\u00b0 + 70\u00b0
\n\u2234 1150\u00b0-\u0b95\u0bcd\u0b95\u0bbe\u0ba9 \u0b87\u0ba3\u0bc8 \u0bae\u0bc1\u0ba9\u0bc8\u0baf\u0b95\u0bcd \u0b95\u0bcb\u0ba3\u0bae\u0bcd =70\u00b0<\/p>\n

(iv)-270″
\n\u21d2 -270\u00b0 =-360\u00b0 + 900
\n\u21d2 -270\u00b0 – 90\u00b0 = -360\u00b0
\n\u2234 -270\u00b0-\u0b95\u0bcd\u0b95\u0bbe\u0ba9 \u0b87\u0ba3\u0bc8 \u0bae\u0bc1\u0ba9\u0bc8\u0baf\u0b95\u0bcd \u0b95\u0bcb\u0ba3\u0bae\u0bcd = 90\u00b0<\/p>\n

(v) -450\u00b0
\n\u21d2 -450\u00b0 =-720\u00b0 + 2700
\n\u21d2 -450\u00b0 -270\u00b0 =-7200
\n\u2234 450\u00b0 – \u0b95\u0bcd\u0b95\u0bbe\u0ba9 \u0b87\u0ba3\u0bc8 \u0bae\u0bc1\u0ba9\u0bc8\u0baf\u0b95\u0bcd \u0b95\u0bcb\u0ba3\u0bae\u0bcd = 270\u00b0<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 3.
\na cos \u03b8 – b sin \u03b8 = c \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, a sin \u03b8 + b cos \u03b8 = \u00b1\\(\\sqrt{a^{2}+b^{2}-c^{2}}\\) \u0b8e\u0ba9\u0bcd\u0baa\u0ba4\u0bc8 \u0ba8\u0bbf\u0bb1\u0bc1\u0bb5\u0bc1\u0b95.
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\na cos \u03b8 – b sin \u03b8 = c \u0b8e\u0ba9\u0ba4\u0bcd \u0ba4\u0bb0\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f\u0bc1\u0bb3\u0bcd\u0bb3\u0ba4\u0bc1
\n– (a cos \u03b8 – b sin \u03b8)2<\/sup> = (c)2<\/sup>
\n\u21d2 a2<\/sup> cos2<\/sup> \u03b8 + b2<\/sup> sin2<\/sup> \u03b8 – 2ab cos \u03b8 sin \u03b8 = C2<\/sup>
\n\u21d2 a2<\/sup> (1 – sin2<\/sup>\u03b8) + b2<\/sup>(1 – cos2<\/sup>\u03b8) – 2ab cos \u03b8 sin \u03b8 = c2<\/sup>
\n\u21d2 a2<\/sup> – a2<\/sup> sin2<\/sup>\u03b8 + b2<\/sup> cos2<\/sup> \u03b8 – 2ab cos \u03b8 sin \u03b8 = c2<\/sup>
\n\u21d2 – a2<\/sup> sin2<\/sup> \u03b8 – b2<\/sup> cos2<\/sup> \u03b8 – 2ab cos \u03b8 sin \u03b8 = c2<\/sup> – a2<\/sup> – b2<\/sup>
\n\u21d2 a2<\/sup> sin2<\/sup> \u03b8 + b2<\/sup> cos2<\/sup> \u03b8 + 2ab cos \u03b8 sin \u03b8 = a2<\/sup> + b2<\/sup> – c2<\/sup>
\n\u21d2 (a sin \u03b8 + b cos \u03b8) = a2<\/sup> + b2<\/sup> – c2<\/sup>
\n\u21d2 a sin \u03b8 + b cos \u03b8 = \u00b1\\(\\sqrt{a^{2}+b^{2}-c^{2}}\\)<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 4.
\nsin \u03b8 + cos \u03b8 = m \u0ba9\u0bc6\u0bb2\u0bcd, cos6<\/sup>\u03b8 + sin6<\/sup>\u03b8 = \\(\\frac{4-3\\left(m^{2}-1\\right)^{2}}{4}\\) \u0b8e\u0ba9 \u0ba8\u0bbf\u0bb1\u0bc1\u0bb5\u0bc1\u0b95. (\u0b87\u0b99\u0bcd\u0b95\u0bc1 m2<\/sup> \u2264 2)
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\nsin \u03b8 + cos \u03b8 = m \u0b8e\u0ba9 \u0ba4\u0bcd \u0ba4\u0bb0\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f\u0bc1\u0bb3\u0bcd\u0bb3\u0ba4\u0bc1
\nLHS = cos6<\/sup>\u03b8 + sin6<\/sup>\u03b8
\n= (cos2<\/sup>\u03b8)3<\/sup> + (sin2<\/sup>\u03b8)3<\/sup>
\n\u2234 (a + b)3<\/sup> = (a + b) (a2<\/sup> – ab + b2<\/sup>)
\n= (cos2<\/sup>\u03b8 + sin2<\/sup>\u03b8)
\n(cos4<\/sup>\u03b8 – cos2<\/sup>\u03b8 sin2<\/sup>\u03b8 + sin4<\/sup>\u03b8)
\n= 1 (cos4<\/sup>\u03b8 – cos2<\/sup>\u03b8 sin2<\/sup>\u03b8 + sin4<\/sup>\u03b8) [\u2235 cos2<\/sup>\u03b8 + sin2<\/sup>\u03b8 = 1]
\n= (cos2<\/sup>\u03b8)2<\/sup> + (sin2<\/sup>\u03b8)2<\/sup> – 3cos2<\/sup>\u03b8 sin2<\/sup>\u03b8) [\u2235 a2<\/sup> + b2<\/sup> = (a + b)2<\/sup> \u2013 2ab]
\n= 1 – 3 sin2<\/sup>\u03b8 cos2<\/sup>\u03b8
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 5.
\n\\(\\frac{\\cos ^{4} \\alpha}{\\cos ^{2} \\beta}+\\frac{\\sin ^{4} \\alpha}{\\sin ^{2} \\beta}\\) = 1, \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd,
\n(i) sin4<\/sup>\u03b1 + sin4<\/sup>\u03b2 = 2 sin2<\/sup>\u03b1 sin 2<\/sup>\u03b2
\n(ii) \\(\\frac{\\cos ^{4} \\beta}{\\cos ^{2} \\alpha}+\\frac{\\sin ^{4} \\beta}{\\sin ^{2} \\alpha}\\) = 1 \u0b8e\u0ba9 \u0ba8\u0bbf\u0bb1\u0bc1\u0bb5\u0b95.
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n\"Samacheer
\n\"Samacheer<\/p>\n

(i) sin4<\/sup>\u03b1 + sin4<\/sup>\u03b2 = 2 sin2<\/sup>\u03b1 sin 2<\/sup>\u03b2
\nLHS = sin4<\/sup>\u03b1 + sin4<\/sup>\u03b2
\n= (sin2<\/sup>\u03b1 sin2<\/sup>\u03b2)2<\/sup> + 2 sin2<\/sup>\u03b1 sin2<\/sup>\u03b2
\n[\u2235 sin2<\/sup>\u03b1 = sin2<\/sup>\u03b2]
\n(\u0bae\u0bc7\u0bb1\u0bcd\u0b95\u0ba3\u0bcd\u0b9f \u0b9a\u0bae\u0ba9\u0bcd\u0baa\u0bbe\u0b9f\u0bc1 (2) – \u0b87\u0bb2\u0bcd \u0b87\u0bb0\u0bc1\u0ba8\u0bcd\u0ba4\u0bc1)
\nLHS = 2 sin2<\/sup>\u03b1 sin2<\/sup>\u03b2 = RHS
\n\u0b8e\u0ba9\u0bb5\u0bc7 \u0ba8\u0bbf\u0bb0\u0bc2\u0baa\u0bbf\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f\u0ba4\u0bc1<\/p>\n

(ii) \\(\\frac{\\cos ^{4} \\beta}{\\cos ^{2} \\alpha}+\\frac{\\sin ^{4} \\beta}{\\sin ^{2} \\alpha}\\) = 1
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 6.
\ny = \\(\\frac{2 \\sin \\alpha}{1+\\cos \\alpha+\\sin \\alpha}\\) \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, \\(\\frac{1-\\cos \\alpha+\\sin \\alpha}{1+\\sin \\alpha}\\) = y \u0b8e\u0ba9 \u0ba8\u0bbf\u0bb1\u0bc1\u0bb5\u0bc1\u0b95.
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n\"Samacheer
\n\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 7.
\n\"Samacheer
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n\"Samacheer
\n\"Samacheer
\n\"Samacheer
\n\u2234 x + y + z = xyz \u0b8e\u0ba9\u0bb5\u0bc7 \u0ba8\u0bbf\u0bb0\u0bc2\u0baa\u0bbf\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f\u0ba4\u0bc1.<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 8.
\ntan2<\/sup>\u03b8 = 1 – k2<\/sup> \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, sec \u03b8 + tan3<\/sup>\u03b8 cosec \u03b8 =(2 – k2<\/sup>)3\/2<\/sup> \u0b8e\u0ba9 \u0ba8\u0bbf\u0bb1\u0bc1\u0bb5\u0bc1\u0b95. \u0bae\u0bc7\u0bb2\u0bc1\u0bae\u0bcd \u0b87\u0bb5\u0bb1\u0bcd\u0bb1\u0bc8 \u0ba8\u0bbf\u0bb1\u0bc8\u0bb5\u0bc1 \u0b9a\u0bc6\u0baf\u0bcd\u0baf\u0bc1\u0bae\u0bcd k \u0b87\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc8\u0b95\u0bcd \u0b95\u0bbe\u0ba3\u0bcd\u0b95.
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n\"Samacheer
\n\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 9.
\nsec \u03b8 + tan \u03b8 = p \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, sec \u03b8, tan \u03b8, \u0baa\u0bb1\u0bcd\u0bb1\u0bc1\u0bae\u0bcd sin \u03b8 \u0b86\u0b95\u0bbf\u0baf\u0bb5\u0bb1\u0bcd\u0bb1\u0bbf\u0ba9\u0bcd \u0bae\u0ba4\u0bbf\u0baa\u0bcd\u0baa\u0bc8 p \u0b87\u0ba9\u0bcd \u0bb5\u0bbe\u0baf\u0bbf\u0bb2\u0bbe\u0b95\u0b95\u0bcd \u0b95\u0bbe\u0ba3\u0bcd\u0b95.
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 10.
\ncot \u03b8 (1 + sin \u03b8) = 4 m \u0baa\u0bbf\u0bb1\u0bcd\u0bb1\u0bc1\u0bae\u0bcd cot \u03b8 (1 – sin \u03b8) = 4n \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, (m2<\/sup> – n2<\/sup>)2<\/sup> = mn \u0b8e\u0ba9 \u0ba8\u0bbf\u0bb1\u0bc1\u0bb5\u0bc1\u0b95.
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\ncot \u03b8(1 + sin \u03b8) = 4m
\n\u21d2 cot \u03b8 + cot \u03b8 sin \u03b8 = 4m
\n\u21d2 cot \u03b8 – cot \u03b8 sin \u03b8 = 4n
\n\u21d2 cot \u03b8 + \\(\\frac{\\cos \\theta}{\\sin \\theta}\\) \u00d7 sin \u03b8 = 4m
\n\u21d2 cot \u03b8 – \\(\\frac{\\cos \\theta}{\\sin \\theta}\\) \u00d7 sin \u03b8 = 4n
\n\u21d2 cot \u03b8 + cos \u03b8 = 4m ……. (1)
\ncot \u03b8 – cos \u03b8 = 4n …….(2)
\n(1), (2) \u0b90 \u0bb5\u0bb0\u0bcd\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bc1\u0ba4\u0bcd\u0ba4\u0bbf (1)-\u0bb2\u0bbf\u0bb0\u0bc1\u0ba8\u0bcd\u0ba4\u0bc1 (2) \u0b90\u0b95\u0bcd \u0b95\u0bb4\u0bbf\u0b95\u0bcd\u0b95
\n(cot \u03b8 + cos \u03b8)2<\/sup> – (cot \u03b8 – cos \u03b8)2<\/sup> = (4m)2<\/sup> – (4n)2<\/sup> cot2<\/sup>\u03b8 + 2 cot \u03b8 \u2219 cos \u03b8 + cos2<\/sup>\u03b8 – (cot2<\/sup>\u03b8 – 2 cot \u03b8 cos \u03b8 + cos2<\/sup> \u03b8) – 16(m2<\/sup> – n2<\/sup>)
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 11.
\ncosec \u03b8 – sin \u03b8 = a3<\/sup> \u0baa\u0bbf\u0bb1\u0bcd\u0bb1\u0bc1\u0bae\u0bcd sec \u03b8 – cos \u03b8 = b3<\/sup> \u0b8e\u0ba9\u0bbf\u0bb2\u0bcd, a2<\/sup>b2<\/sup> (a2<\/sup> + b2<\/sup>) = 1 \u0b8e\u0ba9 \u0ba8\u0bbf\u0bb1\u0bc1\u0bb5\u0bc1\u0b95.
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n\"Samacheer
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

\u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 12.
\na sec \u03b8 – c tan \u03b8 = b \u0baa\u0bbf\u0bb1\u0bcd\u0bb1\u0bc1\u0bae\u0bcd b sec \u03b8 + d tan \u03b8 = c \u0b86\u0b95\u0bbf\u0baf \u0b9a\u0bae\u0ba9\u0bcd\u0baa\u0bbe\u0b9f\u0bc1\u0b95\u0bb3\u0bbf\u0bb2\u0bbf\u0bb0\u0bc1\u0ba8\u0bcd\u0ba4\u0bc1 \u03b8 \u0b90 \u0ba8\u0bc0\u0b95\u0bcd\u0b95\u0bc1\u0b95.
\n\u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1:
\n\"Samacheer
\n\"Samacheer<\/p>\n","protected":false},"excerpt":{"rendered":"

Tamilnadu State Board New Syllabus Samacheer Kalvi 11th Maths Guide Pdf Chapter 3 \u0b85\u0b9f\u0bbf\u0baa\u0bcd\u0baa\u0b9f\u0bc8 \u0b87\u0baf\u0bb1\u0bcd\u0b95\u0ba3\u0bbf\u0ba4\u0bae\u0bcd Ex 3.1 Textbook Questions and Answers, Notes. TN Board 11th Maths Solutions Chapter 3 \u0b85\u0b9f\u0bbf\u0baa\u0bcd\u0baa\u0b9f\u0bc8 \u0b87\u0baf\u0bb1\u0bcd\u0b95\u0ba3\u0bbf\u0ba4\u0bae\u0bcd Ex 3.1 \u0b95\u0bc7\u0bb3\u0bcd\u0bb5\u0bbf 1. \u0b95\u0bca\u0b9f\u0bc1\u0b95\u0bcd\u0b95\u0baa\u0bcd\u0baa\u0b9f\u0bcd\u0b9f \u0b95\u0bcb\u0ba3\u0b99\u0bcd\u0b95\u0bb3\u0bcd \u0b8e\u0ba8\u0bcd\u0ba4\u0b95\u0bcd \u0b95\u0bbe\u0bb1\u0bcd\u0baa\u0b95\u0bc1\u0ba4\u0bbf\u0baf\u0bbf\u0bb2\u0bcd \u0b85\u0bae\u0bc8\u0baf\u0bc1\u0bae\u0bcd \u0b8e\u0ba9\u0bcd\u0baa\u0ba4\u0bc8\u0b95\u0bcd \u0b95\u0bbe\u0ba3\u0bcd\u0b95. (i) 25\u00b0 (ii) 825\u00b0 (iii) -55\u00b0 (iv) 328\u00b0 (v) -230\u00b0 \u0ba4\u0bc0\u0bb0\u0bcd\u0bb5\u0bc1: (i) 25\u00b0 […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[7],"tags":[],"blocksy_meta":"","jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/50209"}],"collection":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/comments?post=50209"}],"version-history":[{"count":0,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/50209\/revisions"}],"wp:attachment":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/media?parent=50209"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/categories?post=50209"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/tags?post=50209"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}