{"id":627,"date":"2021-02-23T09:30:19","date_gmt":"2021-02-23T04:00:19","guid":{"rendered":"https:\/\/wordpress-505192-1602719.cloudwaysapps.com\/?p=627"},"modified":"2021-02-23T09:53:21","modified_gmt":"2021-02-23T04:23:21","slug":"samacheer-kalvi-9th-maths-chapter-2-ex-2-6","status":"publish","type":"post","link":"https:\/\/samacheerguru.com\/samacheer-kalvi-9th-maths-chapter-2-ex-2-6\/","title":{"rendered":"Samacheer Kalvi 9th Maths Solutions Chapter 2 Real Numbers Ex 2.6"},"content":{"rendered":"

You can Download Samacheer Kalvi 9th Maths Book Solutions<\/a>\u00a0Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.<\/p>\n

Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 2 Real Numbers Ex 2.6<\/h2>\n

Ex 2.6 Class 9 Question 1.<\/strong>
\nSimplify the following using addition and subtraction properties of surds:
\n(i) 5\\(\\sqrt { 3 }\\) + 18\\(\\sqrt { 3 }\\) – 2\\(\\sqrt{3}\\)
\n(ii) 4\\(\\sqrt [ 3 ]{ 5 }\\) + 2\\(\\sqrt [ 2 ]{ 5 }\\) – 3\\(\\sqrt [ 3 ]{ 5 }\\)
\n(iii) 3\\(\\sqrt { 75 }\\) + 5\\(\\sqrt { 48 }\\) – \\(\\sqrt { 243 }\\)
\n(iv) 5\\(\\sqrt [ 3 ]{ 40 }\\) + 2\\(\\sqrt [ 3 ]{ 625 }\\) – 3\\(\\sqrt [ 3 ]{ 320 }\\)
\nSolution:
\n(i) 5\\(\\sqrt { 3 }\\) + 18\\(\\sqrt { 3 }\\) – 2\\(\\sqrt { 3 }\\) = (5 + 18 – 2)\\(\\sqrt { 3 }\\) = 21\\(\\sqrt { 3 }\\)
\n(ii) 4\\(\\sqrt [ 3 ]{ 5 }\\) + 2\\(\\sqrt [ 2 ]{ 5 }\\) – 3\\(\\sqrt [ 3 ]{ 5 }\\) = (4 + 2 – 3)\\(\\sqrt [ 3 ]{ 5 }\\) = 3\\(\\sqrt [ 3 ]{ 5 }\\)
\n(iii) 3\\(\\sqrt { 75 }\\) + 5\\(\\sqrt { 48 }\\) – \\(\\sqrt { 243 }\\)
\n\"9th<\/p>\n

(iv) 5\\(\\sqrt [ 3 ]{ 40 }\\) + 2\\(\\sqrt [ 3 ]{ 625 }\\) – 3\\(\\sqrt [ 3 ]{ 320 }\\)
\n\"Ex<\/p>\n

9th Class Maths Exercise 2.6 Solution Question 2.<\/strong>
\nSimplify the following using multiplication and division properties of surds :
\n(i) \\(\\sqrt{3} \\times \\sqrt{5} \\times \\sqrt{2}\\)
\n(ii) \\(\\sqrt { 35 }\\) \u00f7 \\(\\sqrt { 7 }\\)
\n(iii) \\( \\sqrt[3]{27} \\times \\sqrt[3]{8} \\times \\sqrt[3]{125}\\)
\n(iv) (7\\(\\sqrt { a }\\) – 5\\(\\sqrt { b }\\))(7\\(\\sqrt { a }\\) + 5\\(\\sqrt { b }\\))
\n(v) \\([\\sqrt{\\frac{225}{729}}-\\sqrt{\\frac{25}{144}}] \\div \\sqrt{\\frac{16}{81}}\\)
\nSolution:
\n\"9th<\/p>\n

9th Maths Exercise 2.6 Question 3.<\/strong>
\nIf \\(\\sqrt { 7 }\\) =1.414, \\(\\sqrt { 3 }\\) = 1.732, \\(\\sqrt { 5 }\\) = 2.236, \\(\\sqrt { 10 }\\) = 3.162, then find the values of the following correct to 3 places of decimals.
\n(i) \\(\\sqrt{40}-\\sqrt{20}\\)
\n(ii) \\(\\sqrt{300}+\\sqrt{90}-\\sqrt{8}\\)
\nSolution:
\n\"9th<\/p>\n

\"Samacheer<\/p>\n

2.6 9th Class Math Question 4.<\/strong>
\nArrange surds in descending order :
\n(i) \\(\\sqrt[3]{5}, \\sqrt[9]{4}, \\sqrt[6]{3}\\)
\n(ii) \\(\\sqrt[2]{\\sqrt[3]{5}}, \\sqrt[3]{\\sqrt[4]{7}}, \\sqrt{\\sqrt{3}}\\)
\nSolution:
\n(i) \\(\\sqrt[3]{5}, \\sqrt[9]{4}, \\sqrt[6]{3}\\)
\n5\\(\\frac { 1 }{ 3 }\\)<\/sup>
\n\u2234 The order of the surds \\(\\sqrt[3]{5}, \\sqrt[9]{4}, \\sqrt[6]{3}\\) are 3, 9, 6.
\n4\\(\\frac { 1 }{ 9 }\\)<\/sup>
\n3\\(\\frac { 1 }{ 6 }\\)<\/sup> l.c.m of 3, 9, 6 is 18
\n\"Maths
\n\u2234 The descending order of \\(\\sqrt[3]{5}, \\sqrt[9]{4}, \\sqrt[6]{3}\\) is \\((15625)^{\\frac{1}{18}}>(27)^ {\\frac{1}{18}} >16^{\\frac{1}{18}} \\text { i.e. } \\sqrt[3]{5}>\\sqrt[6]{3}>\\sqrt[9]{4}\\)<\/p>\n

(ii) \\(\\sqrt[2]{\\sqrt[3]{5}}, \\sqrt[3]{\\sqrt[4]{7}}, \\sqrt{\\sqrt{3}}\\)
\nThe order of the surds \\(\\sqrt[2]{\\sqrt[3]{5}}, \\sqrt[3]{\\sqrt[4]{7}}, \\sqrt{\\sqrt{3}}\\) are 6, 12, 4
\nl.c.m of 6, 12, 4 is 12
\n\"Class<\/p>\n

Maths Class 9 Exercise 2.6 Solutions Question 5.<\/strong>
\nCan you get a pure surd when you find
\n(i) the sum of two surds
\n(ii) the difference of two surds
\n(iii) the product of two surds
\n(iv) the quotient of two surds
\nJustify each answer with an example.
\nSolution:
\n\"Class<\/p>\n

\"Class<\/p>\n

Class 9 Maths Ex 2.6 Solution Question 6.<\/strong>
\nCan you get a rational number when you compute
\n(i) the sum of two surds
\n(ii) the difference of two surds
\n(iii) the product of two surds
\n(iv) the quotient of two surds
\nJustify each answer with an example.
\nSolution:
\n(i) Yes (5 – \\(\\sqrt{3}\\)) + (5 + \\(\\sqrt{3}\\)) = 10, a rational number
\n(ii) Yes \\((5+\\sqrt[3]{7})-(-6+\\sqrt[3]{7})=11\\), a rational number
\n(iii) Yes (5 + \\(\\sqrt{3}\\) ) (5 – \\(\\sqrt{3}\\) ) = 25 – 3 = 22, a rational number
\n(iv) Yes \\(\\frac{5 \\sqrt{3}}{\\sqrt{3}}=5\\) ,a rational number<\/p>\n","protected":false},"excerpt":{"rendered":"

You can Download Samacheer Kalvi 9th Maths Book Solutions\u00a0Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations. Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 2 Real Numbers Ex 2.6 Ex 2.6 Class 9 Question 1. Simplify the following using addition and subtraction properties of surds: […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":"","footnotes":""},"categories":[3],"tags":[],"blocksy_meta":"","jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/627"}],"collection":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/comments?post=627"}],"version-history":[{"count":0,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/posts\/627\/revisions"}],"wp:attachment":[{"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/media?parent=627"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/categories?post=627"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerguru.com\/wp-json\/wp\/v2\/tags?post=627"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}