Students can Download Maths Chapter 2 Measurements Ex 2.1 Questions and Answers, Notes Pdf, Samacheer Kalvi 7th Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

## Tamilnadu Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 2 Measurements Ex 2.1

**Samacheer Kalvi 7th Maths Term 2 Question 1.**

Find the missing values in the following table for the circles with radius (r), diameter (d) and Circumference (C).

Solution:

(i) Given radius r = 15cm

∴ diameter d = 2 × 15 = 30 cm

Circumference C = π d units

= \(\frac { 22 }{ 7 } \) × 30 = \(\frac { 660 }{ 7 } \) = 94.28 cm

(ii) Given circumference C = 1760 cm

2πr = 1760

2 × \(\frac { 22 }{ 7 } \) × r = 1760

r = \(\frac{1760 \times 7}{2 \times 22}\) = \(\frac{160 \times 7}{2 \times 2}\) = 40 × 7 = 280 cm

diameter = 2 × r

= 2 × 280 = 560 cm

(iii) diameter d = 24m

radius r = \(\frac { d }{ 2 } \) = \(\frac { 24 }{ 2 } \) = 12 m

Circumference C = 2 π r units

= 2 × \(\frac { 22 }{ 7 } \) × 12 = \(\frac { 528 }{ 7 } \) = 75.4 m

Tabulating the results

**7th Maths 2.1 Question 2.**

Diameters of different circles are given below. Find their circumference (Take π = \(\frac { 22 }{ 7 } \) )

(i) d = 70cm

(ii) d = 56m

(iii) d = 28mm

Solution:

(i) Diameter d = 70 cm

Circumference C = π d units = \(\frac { 22 }{ 7 } \) × 70 = 22 × 10 = 220 cm

(ii) Diameter d = 56 m

Circumference = π d units

= \(\frac { 22 }{ 7 } \) × 56 = 22 × 8 = 176 m

(iii) Diameter d = 28 mm

Circumference C = π d units = \(\frac { 22 }{ 7 } \) × 28 = 22 × 4 = 88 mm

**7th Maths Guide Term 2 Question 3.**

Find the circumference of the circles whose radii are given below.

(i) 49 cm

(ii) 91 mm

Solution:

Radius r = 49 cm

Circumference C = 2 π r units = 2 × \(\frac { 22 }{ 7 } \) × 49 = 2 × 22 × 7

= 44 × 7 = 308 cm

(ii) Radius r = 91 mm

Circumference C = 2 π r units

= 2 × \(\frac { 22 }{ 7 } \) × 91 = 2 × 22 × 13 = 44 × 13 = 572 mm

**Samacheer Kalvi 7th Maths Book Answers Question 4.**

The diameter of a circular well is 4.2 m. What is its circumference?

Solution:

Given the diameter d = 4.2 m

Circumference C = π d units = \(\frac { 22 }{ 7 } \) × 4.2 m = 22 × 0.6 = 13.2 m

**Samacheer Kalvi 7th Maths Question 5.**

The diameter of the bullock cart wheel is 1.4 m. Find the distance covered by it in 150 rotations?

Solution:

Diameter of the bullock cart wheel d= 1.4 m

Distance covered in 1 rotation = Its circumference

= π d units = \(\frac { 22 }{ 7 } \) × 1 .4 m = 22 × 0.2 = 4.4 m

Distance covered in one rotation = 4.4 m

Distance covered in 150 rotations = 4.4 × 150 = 660.0

Distance covered in 150 rotations = 660 m

**Samacheer Kalvi 7th Maths Book Term 2 Question 6.**

A ground is in the form of a circle whose diameter is 350 m. An athlete makes 4 revolutions. Find the distance covered by the athlete.

Solution:

Diameter of the ground d = 350 m

Distance covered in 1 revolution = Circumference of the circle

= π d units = \(\frac { 22 }{ 7 } \) × 350 m = 22 × 50 = 1100 m

Distance covered in 1 rotation = 1100 m

Distance covered in 4 revolutions = 1100 × 4 = 4400 m

**Samacheer Kalvi 7th Maths Solutions Question 7.**

A wire of length 1320 cm is made into circular frames of radius 7 cm each. How many frames can be made?

Solution:

Length of the wire = 1320 cm

Radius of each circular frame = 7cm

Circumference of the frame 2 π r units = 2 × \(\frac { 22 }{ 7 } \) × 7 cm = 2 × 22 = 44 cm

30 frames can be made.

**7th Maths Samacheer Kalvi Question 8.**

A Rose garden is in the form of circle of radius 63 m. The gardener wants to fence it at the rate of ₹ 150 per metre. Find the cost of fencing?

Solution:

Radius of the garden r = 63 m

Circumference of the garden = 2 π r units = 2 × \(\frac { 22 }{ 7 } \) × 63 m = 2 × 22 × 9 = 396 m

Cost of fencing 1 meter = ₹ 150

Cost of fencing 396 meter = ₹ 150 × 396 = ₹ 59,400

∴ Cost of fencing the garden = ₹ 59,400

Objective Type Questions

**7th Maths Term 2 Question 9.**

Formula used to find the circumference of a circle is

(i) 2πr units

(ii) πr^{2} + 2r units

(iii) πr^{2} sq. units

(iv) πr^{3} cu. units

Answer:

(i) 2πr units

**Samacheer Kalvi 7th Maths Solution Question 10.**

In the formula, C = 2πr, ‘r’ refers to

(i) circumference

(ii) area

(iii) rotation

(iv) radius

Answer:

(iv) radius

**Samacheer Kalvi 7th Maths Books Answers Question 11.**

If the circumference of a circle is 82π, then the value of ‘r’ is

(i) 41cm

(ii) 82 cm

(iii) 21cm

(iv) 20 cm

Answer:

(i) 41cm

**Samacheer Kalvi 7th Term 2 Maths Solutions Question 12.**

Circumference of a circle is always

(i) three times of its diameter

(ii) more than three times of its diameter

(iii) less than three times of its diameter

(iv) three times of its radius

Answer:

(ii) more than three times of its diameter