Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.18

You can Download Samacheer Kalvi 10th Maths Book Solutions Guide Pdf, Tamilnadu State Board help you to revise the complete Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 10th Maths Solutions Chapter 3 Algebra Ex 3.18

10th Maths Exercise 3.18 Answers Question 1.
If A is of order p × q and B is of order q × r what is the order of AB and BA?
Solution:
If A is of order p × q [∵ p × q q × r = p × r]
the order of AB = p × r [∵ q × r p × q = r ≠ p]
Product of BA cannot be defined/found as the number of columns in B ≠. The number of rows in A.

10th Maths Exercise 3.18 Question 2.
If A is of order p × q and B is of order q × r what is the order of AB and BA?
Answer:
Order of A = a × (a + 3)
Order of B = b × (17 – b)
Given: Product of AB exist
a + 3 = b
a – b = – 3 ….(1)
Product of BA exist
17 – b = a
– a – b = -17
a + b = 17 ………(2)
(1) + (2) ⇒ 2a = 14
a = \(\frac { 14 }{ 2 } \) = 7
Substitute the value of a = 7 in (1)
7 – b = -3 ⇒ -b = -3 -7
-b = -10 ⇒ b = 10
The value of b = 7 and b = 10

Ex 3.18 Class 10 Question 3.
Find the order of the product matrix AB if
10th Maths Exercise 3.18 Answers Samacheer Kalvi
Solution:
10th Maths Exercise 3.18 Answers Algebra Samacheer Kalvi

10th New Syllabus Maths Exercise 3.18 Question 4.
If A = \(\left[\begin{array}{ll}{2} & {5} \\ {4} & {3}\end{array}\right]\), B = \(\left[\begin{array}{cc}{1} & {-3} \\ {2} & {5}\end{array}\right]\) find AB, BA and check if AB = BA?
Solution:
10th Maths Exercise 3.18 Algebra Samacheer Kalvi
Ex 3.18 Class 10 Algebra Samacheer Kalvi

10th Maths Exercise 3.18 Samacheer Kalvi Question 5.
10th New Syllabus Maths Exercise 3.18 Algebra Samacheer Kalvi
Solution:
10th Maths Exercise 3.18 Algebra Samacheer Kalvi
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.18 7
Exercise 3.18 Class 10 Algebra Samacheer Kalvi

Exercise 3.18 Class 10 Question 6.
Show that the matrices A = \(\left[\begin{array}{ll}{1} & {2} \\ {3} & {1}\end{array}\right]\), B = \(\left[\begin{array}{cc}{1} & {-2} \\ {-3} & {1}\end{array}\right]\) satisfy commutative property AB = BA
Solution:
10th Maths Exercise 3.18 Algebra

10th Maths Exercise 3.18 Question 7.
Ex 3.18 Class 10 Samacheer Algebra
(i) A(BC) = (AB)C
(ii) (A – B)C = (AC – BC)
(iii) (A- B)T = AT – BT
Solution:
(i) A(BC) = (AB)C
10th Maths 3.18 Samacheer Kalvi Algebra
10th Maths Exercise 3.18 11th Sum Algebra
Exercise 3.18 Samacheer Kalvi Algebra
10th Maths Exercise 3.18 3rd Sum Algebra

Ex 3.18 Class 10 Samacheer Question 8.
Samacheer Kalvi Guru 10th Maths Algebra
Solution:
Samacheerkalvi.Guru 10th Maths Algebra
Samacheer Kalvi Guru Maths 10th Algebra

10th Maths 3.18 Question 9.
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.18 18
Solution:
Samacheer Kalvi Guru 10th Maths Guide Algebra

Class 10 Samacheer Question 10.
Verify that A2 = I when A = \(\left(\begin{array}{cc}{5} & {-4} \\ {6} & {-5}\end{array}\right)\)
Solution:
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.18 20

10th Maths Exercise 3.18 11th Sum Question 11.
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.18 21
Solution:
10th Maths Exercise 3.18 Answers Algebra Samacheer Kalvi  2

10th Maths Question 12.
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.18 23
Solution:
10th Maths Exercise 3.18 Algebra Samacheer Kalvi  3
Samacheer Kalvi 10th Maths Chapter 3 Algebra Ex 3.18 25

10th Maths Exercise 3.18 3rd Sum Question 13.
If A = \(\) show that A2 – 5A + 7I2 = 0.
Solution:
Ex 3.18 Class 10 Algebra Samacheer Kalvi  5