Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement

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Tamilnadu Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement

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Samacheer Kalvi 11th Physics Nature of Physical World and Measurement TextBook Questions Solved

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Multiple Choice Questions

Nature Of Physical World And Measurement Questions And Answers Question 1.
One of the combinations from the fundamental physical constants is \(\frac{h c}{\mathrm{G}}\). The unit of this expression is
(a) Kg2
(b) m3
(c) S-1
(d) m
Answer:
(a) Kg2

Samacheer Kalvi 11th Physics Solution Chapter 1 Question 2.
If the error in the measurement of radius is 2%, then the error in the determination of volume of the sphere will be …….
(a) 8%
(b) 2%
(c) 4%
(d) 6%
Answer:
(d) 6%

Nature Of Physical World And Measurement Question 3.
If the length and time period of an oscillating pendulum have errors of 1 % and 3% respectively
then the error in measurement of acceleration due to gravity is …… [Related to AMPMT 2008]
(a) 4%
(b) 5%
(c) 6%
(d) 7%
Answer:
(d) 7%

11th Physics Nature Of Physical World And Measurement Question 4.
The length of a body is measured as 3.51 m, if the accuracy is 0.01mm, then the percentage error in the measurement is ……
(a) 351%
(b) 1%
(c) 0.28%
(d) 0.035%
Answer:
(c) 0.28%

Nature Of Physical World And Measurement Class 11 Question 5.
Which of the following has the highest number of significant figures?
(a) 0.007 m2
(b) 2.64 × 1024 kg
(c) 0.0006032 m2
(d) 6.3200 J
Answer:
(d) 6.3200 J

Samacheer Kalvi Guru 11th Physics Question 6.
If π = 3.14, then the value of π2 is …..
(a) 9.8596
(b) 9.860
(c) 9.86
(d) 9.9
Answer:
(c) 9.86

Samacheerkalvi.Guru 11th Physics Question 7.
Which of the following pairs of physical quantities have same dimension?
(a) force and power
(b) torque and energy
(c) torque and power
(d) force and torque
Answer:
(b) torque and energy

Physical World And Measurement Class 11 Questions Question 8.
The dimensional formula of Planck’s constant h is [AMU, Main, JEE, NEET]
(a) [ML2T-1]
(b) [ML2T-3]
(c) [MLTT-1]
(d) [MLTT3-3]
Answer:
(a) [ML2T-1]

Nature Of Physical World And Measurement In Tamil Question 9.
The velocity of a particle v at an instant t is given by v = at + bt2. The dimensions of b is ……
(a) [L]
(b) [LT-1]
(c) [LT-2]
(d) [LT-3]
Answer:
(d) [LT-3]

11th Physics Unit 1 Question 10.
The dimensional formula for gravitational constant G is [Related to AIPMT 2004]
(a) [ML-3T-2]
(b) [M-1L3T-2]
(c) [M-1L-3T-2]
(d) [ML-3T2]
Answer:
(b) [M-1L3T-2]

Samacheer Kalvi Guru 11 Physics Question 11.
The density of a material in CGS system of units is 4 g cm-3. In a system of units in which unit of length is 10 cm and unit of mass is 100 g, then the value of density of material will be ……
(a) 0.04
(b) 0.4
(c) 40
(d) 400
Answer:
(c) 40

11th Physics Samacheer Solutions Question 12.
If the force is proportional to square of velocity, then the dimension of proportionality constant
is [JEE-2000] ……
(a) [MLT0]
(b) [MLT-1]
(c) [ML-2T]
(d) [ML-1T0]
Answer:
(d) [ML-1T0]

Nature Of Physical World And Measurement Class 11 Notes Question 13.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 1213 [MainAIPMT2011]
(a) length
(b) time
(c) velocity
(d) force
Answer:
(c) velocity

Physical World Class 11 Questions And Answers Pdf Question 14.
Planck’s constant (h), speed of light in vaccum (c) and Newton’s gravitational constant (G) are taken as three fundamental constants. Which of the following combinations of these has the dimension of length? [NEET 2016 (Phase II)]
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 1214
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 7

Samacheer Kalvi.Guru 11th Physics Question 15.
A length-scale (l) depends on the permittivity (ε) of a dielectric material, Boltzmann constant (kB), the absolute temperature (T), the number per unit volume (n) of certain charged particles, and the charge (q) carried by each of the particles. Which of the following expression for l is dimensionally correct?. [JEE (advanced) 2016]
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 8
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 9

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Short Answer Questions

11th Samacheer Physics Solutions Question 1.
Briefly explain the types of physical quantities.
Answer:
Physical quantities are classified into two types. They are fundamental and derived quantities.
(i) Fundamental (or) base quantities – The physical quantities which cannot be expressed in terms of any other physical quantities are fundamental or base quantities.
Example: Length, mass, time, electric current, temperature, luminous intensity, and amount of substance.

(ii) Derived quantities – The physical quantities that can be expressed in terms of fundamental quantities are called derived quantities.
Example: area, volume, density velocity, acceleration, force.

11 Samacheer Physics Solutions Question 2.
How will you measure the diameter of the Moon using parallax method?
Answer:
Let θ is the angular diameter of moon
d – is the distance of moon from earth, from figure, θ = \(\frac{\mathrm{D}}{d}\)
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 10
Diameter of moon D = d.θ
by knowing θ, d, diameter of moon can be calculated

Samacheer Kalvi 11th Physics Solution Book Question 3.
Write the rules for determining significant figures.
Answer:
Rules for counting significant figures:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 12
Note: 1 Multiplying or dividing factors, which are neither rounded numbers nor numbers representing measured values, are exact and they have infinite numbers of significant figures as per the situation.
For example, circumference of circle S = 2πr, Here the factor 2 is exact number. It can be written as 2.0, 2.00 or 2.000 as required.
Note: 2 The power of 10 is irrelevant to the determination of significant figures.
For example x = 5.70 m = 5.70 × 102 cm = 5.70 × 103 mm = 5.70 × 10-3 km.
In each case the number of significant figures is three.

Samacheer Kalvi Class 11 Physics Solutions Question 4.
What are the limitations of dimensional analysis?
Answer:
Limitations of Dimensional analysis
1. This method gives no information about the dimensionless constants in the formula like 1, 2, ……… π, e, etc.
This method cannot decide whether the given quantity is a vector or a scalar.
This method is not suitable to derive relations involving trigonometric, exponential and logarithmic functions.
It cannot be applied to an equation involving more than three physical quantities.
It can only check on whether a physical relation is dimensionally correct but not the correctness of the relation. For example, using dimensional analysis, Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 13 is dimensionally correct whereas the correct relation is Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 132

Physics Class 11 Chapter 1 Question 5.
Define precision and accuracy. Explain with one example.
Answer:
(i) Accuracy – “The accuracy of measurement is a measure of how close the measured value is to the true value of the quantity”.
For example, the true value of a certain length is near 3.678cm. If we measure the length and get it out as 3.6cm 3.4cm and 3.5cm respectively in three various measurements, obviously, 3.6cm is more accurate than other values as it is nearer to the true value.

(ii) Precision – Precision tells us to what resolution or limit the physical quantity is measured. If the measurement is precise that does not necessarily mean that it is accurate. However, if the measurement is consistently accurate it is also precise.

For example, if the temperature outside the building is 40°C, then the thermometer is accurate. If the thermometer consistently registers this exact temperature in a row, then the thermometer is precise.

Also if a temperature of a refrigerator is registered as 10.2‘C, 10.4°C 10.1°C, 10.2°C in a row, and the true value is 9°C, then the thermometer is precise but not accurate.

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Long Answer Questions

Samacheer Kalvi 11th Physics Question 1.
(i) Explain the use of screw gauge and vernier caliper in measuring smaller distances.
Answer:
(i) Measurement of small distances: screw gauge and vernier caliper Screw gauge:
The screw gauge is an instrument used for measuring accurately the dimensions of objects up to a maximum of about 50 mm. The principle of the instrument is the magnification of linear motion using the circular motion of a screw. The least count of the screw gauge is 0.01 mm. Vernier caliper: A vernier caliper is a versatile instrument for measuring the dimensions of an object namely the diameter of a hole, or a depth of a hole. The least count of the vernier caliper is 0.1 mm.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 20
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 21
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 22

(ii) Write a note on the triangulation method and radar method to measure larger distances. Triangulation method for the height of an accessible object;
Let AB = h be the height of the tree or tower to be measured. Let C be the point of observation at distance x from B. Place a range finder at C and measure the angle of elevation, ACB = θ as shown in the figure.
From right-angled triangle ABC,
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 23
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 24
(or) height h = x tan θ
Knowing the distance x, the height h can be determined.
RADAR method
The word RADAR stands for radio detection and ranging. Radar can be used to measure accurately the distance of a nearby planet such as Mars. In this method, radio waves are sent from transmitters which, after reflection from the planet, are detected by the receiver. By measuring, the time interval (t) between the instants the radio waves are sent and received, the distance of the planet can be determined as where v is the speed of the radio wave. As the time is taken (t) is for the distance covered during the forward and backward path of the radio waves, it is divided by 2 to get the actual distance of the object. This method can also be used to determine the height, at which an airplane flies from the ground.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 25

Samacheer Kalvi 11th Physics Solution Question 2.
Explain in detail the various types of errors.
Answer:
The uncertainty in a measurement is called an error. Random error, systematic error and gross error are the three possible errors.
(i) Systematic errors: Systematic errors are reproducible inaccuracies that are consistently *, in the same direction. These occur often due to a problem that persists throughout the experiment. Systematic errors can be classified as follows
(1) Instrumental errors: When an instrument is not calibrated properly at the time of manufacture, instrumental errors may arise. If a measurement is made with a meter scale whose end is worn out, the result obtained will have errors. These errors can be corrected by choosing the instrument carefully.
(2) Imperfections in experimental technique or procedure: These errors arise due to the limitations in the experimental arrangement. As an example, while performing experiments with a calorimeter, if there is no proper insulation, there will be radiation losses. This results in errors and to overcome these, necessary correction has to be applied
(3) Personal errors: These errors are due to individuals performing the experiment, may be due to incorrect initial setting up of the experiment or carelessness of the individual making the observation due to improper precautions.
(4) Errors due to external causes: The change in the external conditions during an experiment can cause error in measurement. For example, changes in temperature, humidity, or pressure during measurements may affect the result of the measurement.
(5) Least count error: Least count is the smallest value that can be measured by the measuring instrument, and the error due to this measurement is least count error. The instrument’s
resolution hence is the cause of this error. Least count error can be reduced by using a high precision instrument for the measurement.
(ii) Random errors: Random errors may arise due to random and unpredictable variations in
experimental conditions like pressure, temperature, voltage supply etc. Errors may also be due to personal errors by the observer who performs the experiment. Random errors are sometimes called “chance error”. When different readings are obtained by a person every time he repeats the experiment, personal error occurs. For example, consider the case of the thickness of a wire measured using a screw gauge. The readings taken may be different for different trials. In this case, a large number of measurements are made and then the arithmetic mean is taken.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 26

11th Physics Samacheer Answers Question 3.
What do you mean by the propagation of errors? Explain the propagation of errors in addition and multiplication.
Answer:
A number of measured quantities may be involved in the final calculation of an experiment. Different types of instruments might have been used for taking readings. Then we may have to look at the errors in measuring various quantities, collectively.
The error in the final result depends on
(i) The errors in the individual measurements
(ii) On the nature of mathematical operations performed to get the final result. So we should know the rules to combine the errors.
The various possibilities of the propagation or combination of errors in different mathematical operations are discussed below:
(i) Error in the sum of two quantities
Let ∆A and ∆B be the absolute errors in the two quantities A and B respectively. Then, Measured value of A = A ± ∆A
Measured value of B = B ± ∆B
Consider the sum, Z = A + B
The error ∆Z in Z is then given by
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 27
The maximum possible error in the sum of two quantities is equal to the sum of the absolute errors in the individual quantities.
Error in the product of two quantities: Let ∆A and ∆B be the absolute errors in the two quantities A, and B, respectively. Consider the product Z = AB
The error ∆Z in Z is given by Z ± ∆Z = (A ± ∆A) (B ± ∆B)
= (AB) ± (A ∆ B) ± (B ∆ A) ± (∆A • ∆B)
Dividing L.H.S by Z and R.H.S by AB, we get,
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 28
As ∆A/A, ∆B/B are both small quantities, their product term Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 1215 can be neglected.
The maximum fractional error in Z is
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 1216

11th Physics Solutions Samacheer Kalvi Question 4.
Write a short note on the following:
(a) Unit
(b) Rounding – off
(c) Dimensionless quantities
Answer:
(a) Unit: An arbitrarily chosen standard of measurement of a quantity, which is accepted internationally is called a unit of the quantity.
The units in which the fundamental quantities are measured are called fundamental or base units and the units of measurement of all other physical quantities, which can be obtained by a suitable multiplication or division of powers of fundamental units, are called derived units.

(b) Rounding – off: In no case should the result have more significant figures than die figures involved in the data used for calculation. The result of calculation with numbers containing more than one uncertain digit should be rounded off. The rules for rounding off are given below.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 30
(c) Dimensionless quantities: On the basis of dimension, dimensionless quantities are classified into two categories.

  • Dimensionless variables: Physical quantities that have no dimensions, but have variable values are called dimensionless variables. Examples are specific gravity, strain, refractive index etc.
  • Dimensionless Constant: Quantities which have constant values and also have no dimensions are called dimensionless constants. Examples are π, e, numbers, etc.

Samacheer Kalvi 11th Physics Guide Question 5.
Explain the principle of homogeneity of dimensions. What are its uses? Give example.
Answer:
The principle of homogeneity of dimensions states that the dimensions of all the terms in a physical expression should be the same. For example, in the physical expression v2 = u2 + 2as, the dimensions of v2, u2 and 2 as are the same and equal to [L2T-2].
(i) To convert a physical quantity from one system of units to another: This is based on the fact that the product of the numerical values (n) and its corresponding unit (u) is a constant, i.e, = constant n1[u1] = constant (or) n1[u1] = n2[u2].
Consider a physical quantity which has dimension ‘a’ in mass, ‘b’ in length and ‘c’ in time. If the fundamental units in one system are M1, L1 and T1 and the other system are M2, L2 and T2 respectively, then we can write, Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 31
We have thus converted the numerical value of physical quantity from one system of units into the other system.
Example: Convert 76 cm of mercury pressure into Nm-2 using the method of dimensions. Solution: In cgs system 76 cm of mercury pressure = 76 × 13.6 × 980 dyne cm-2
The dimensional formula of pressure P is [ML-1T-2]

(ii) To check the dimensional correctness of a given physical equation:
Example: The equation \(\frac{1}{2} m v^{2}\) = mgh can be checked by using this method as follows.
Solution: Dimensional formula for
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 311
Dimensional formula for
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 32
Both sides are dimensionally the same, hence the equation is dimensionally correct.
(iii) To establish the relationships among various physical quantities:
Example: An expression for the time period T of a simple pendulum can be obtained by using this method as follows.
Let true period T depend upon
(i) mass m of the bob
(ii) length l of the pendulum and
(iii) acceleration due to gravity g at the place where the pendulum is suspended. Let the constant involved is K = 2π.
Solution:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 312
Here k is the dimensionless constant. Rewriting the above equation with dimensions.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 321
Comparing the powers of M, L and T on both sides, a – 0, b + c = 0, -2c = 1
Solving for a, b and c a = 0, b = 1/2, and c = -1/2
From the above equation
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 33

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Numerical Problems

Samacheer Kalvi 11th Physics Book Solutions Question 1.
In a submarine equipped with sonar, the time delay between the generation of a pulse and its echo after reflection from an enemy submarine is observed to be 80 sec. If the speed of sound in water is 1460 ms-1. What is the distance of the enemy submarine?
Answer:
Given:
Speed of sound in water = 1460 ms-1
Time delay = 80s
Distance of enemy ship = ?
Solution:
Total distance covered = speed × time
= 1460 ms-1 × 80s = 116800 m
Time taken is for forward and backward path of sound waves.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 34
= 58400 m (or) 58.4 km

Samacheer Kalvi 11 Physics Question 2.
The radius of the circle is 3.12 m. Calculate the area of the circle with regard to significant figures.
Answer:
r = 3.12 m
A = ?
A = πr²
= 3.14 x 3.12 x 3.12
= 3.14 x 9.7344
= 30.566016
A = 30.6 m²

Units And Measurements Class 11 Questions Answers Question 3.
Assuming that the frequency v of a vibrating string may depend upon
(i) applied force (F)
(ii) length (l)
(iii) mass per unit length (m), prove that Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 315 using dimensional analysis. [Related to JIPMER 2001]
Answer:
Given: The frequency v of a vibrating string depends
(i) applied force (F)
(ii) length (l)
(iii) mass per unit length (m)
Solution:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 351
Substitute the dimensional formulae of the above quantities
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 36
Comparing the powers of M, L, T on both sides,
x + z = 0, x + y – z = 0, -2x = -1
Solving for x, y, z, we get
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 37
Substitute x, y, z values in equ(1)
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 38

Samacheer Kalvi 11 Physics Solutions Question 4.
Jupiter is at a distance of 824.7 million km from the Earth. Its angular diameter is measured to be 35.72″. Calculate the diameter of Jupiter.
Answer:
D = 824.7 x 109m
∝ = 35.72″= Jupiter angular diameter
∝ =35.72″ X 4.85 x 10-6 = 173.242 x 10-6rad
= 1.73242 x 10-4rad
d = ∝ D
= 1.73242 x 10-4 x 8.247 x 1011
= 14.287 x 107
= 14.287 x 108 m
d = 14.287 x 105 Km

Samacheer Kalvi 11th Physics Solutions Question 5.
The measurement value of the length of a simple pendulum is 20 cm known with 2 mm accuracy. The time for 50 oscillations was measured to be 40 s within 1 s resolution. Calculate the percentage of accuracy in the determination of acceleration due to gravity ‘g’ from the above measurement.
Answer:
Given,
Length of simple pendulum (l) = 20 cm
absolute error in length (∆l) = 2 mm = 0.2 cm
Time taken for 50 oscillation (t) = 40 s
error in time ∆T = 1 s
Solution: Time period for one oscillation (T)
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 39
Hence, the percentage error in g is
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 40

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Conceptual Questions

Question 1.
Why is it convenient to express the distance of stars in terms of light-year (or) parsec rather than in km?
Answer:
A parsec is 206, 265 AU and is roughly the distance to the nearest stars. If we were to view a giant star with a diameter of 1 AU at a distance of one parsec, it would appear to be just 1/3600th of a degree in angular size. For comparison, the sun and moon are both half a degree in angular size when viewed from Earth.

Question 2.
Show that a screw gauge of pitch 1 mm and 100 divisions is more precise than a vernier caliper with 20 divisions on the sliding scale.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 41
As shown, the least count of screw gauge is lesser than vernier caliper, hence screw gauge is more precise.

Question 4.
Having all units in atomic standards is more useful. Explain.
Answer:
An atomic mass unit (symbolized AMU or amu) is defined as precisely 1/12 the mass of an atom of carbon-12. The carbon-12 (C-12) atom has six protons and six neutrons in its nucleus.
In imprecise terms, one AMU is the average of the proton rest mass and the neutron rest mass. This is approximately 1.67377 × 10-27 kilogram (kg), or 1.67377 × 10-24 gram (g). The mass of an atom in AMU is roughly equal to the sum of the number of protons and neutrons in the nucleus.
The AMU is used to express the relative masses of, and thereby differentiate between, various isotopes of elements. Thus, for example, uranium-235 (U-235) has an AMU of approximately 235, while uranium-238 (U-238) is slightly more massive. The difference results from the fact that U-238, the most abundant naturally occurring isotope of uranium, has three more neutrons than U-235, an isotope that has been used in nuclear reactors and atomic bombs.

Question 5.
Why dimensional methods are applicable only up to three quantities?
Answer:
Understanding dimensions is of utmost importance as it helps us in studying the nature of physical quantities mathematically. The basic concept of dimensions is that we can add or subtract only those quantities which have same dimensions. Also, two physical quantities are equal if they have same dimensions. these basic ideas help us in deriving the new relation between physical quantities, it is just like units.

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Additional Questions Solved

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Multiple Choose Questions

Question 1.
One light year is equal to
(a) 9.47610 x -12Km
(b) 9.476 x 10-12Km
(c) 9.476 x 1015Km
(d) 9.476 x 10-15Km
Answer:
(b) 9.476 x 10-12Km

Question 2.
One atomus equal to ……
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 401
Answer:
(c) 160 ms

Question 3.
Parallactic second (parsec) is equal to _______.
(a) 3.26 light year
(b) 3.08 x 1016m
(c) 3.08 x 1016m
(d) both a & b
Answer:
(d) both a & b

Question 4.
One Astronomical unit is
(a) 3.153 × 107 m
(b) 1.496 × 107 m
(c) 9.46 × 1012 m
(d) 3.26 × 1015 m
Answer:
(b) 1.496 × 107 m

Question 5.
The dimensional formula for latent heat is _______.
(a) M1 L2T-2
(b) M0 L2 T-2
(c) M0 L-2 T2
(d) M1 L0 T2
Answer:
(b) M0 L2 T-2

Question 6.
One Fermi is …..
(a) 10-9 m
(b) 10-10 m
(c) 10-12 m
(d) 10-15 m
Answer:
(d) 10-15 m

Question 7.
The dimensional formula for the permeability of free space (μ0)_______.
(a) MLT-2A-2
(b) ML2 T-2 A2
(c) M2 L2 T-2 A-2
(d) ML2T2A-2
Answer:
(a) MLT-2A-2

Question 8.
One solar mass is …………..
(a) 2 × 1030 kg
(b) 2 × 1030 g
(c) 2 × 1030 mg
(d) 2 × 1030 tonne
Answer:
(d) 2 × 1030 tonne

Question 9.
If E, M, J, and G denote energy, mass angular momentum, gravitational constant respectively the dimension of EJ²/M5G² is _______.
(a) M3L6T-4
(b) Dimensionless
(c) M0 L4 T6
(d) M3L-6T4
Answer:
(d) M3L-6T4

Question 10.
The word physics is derived from the word …..
(a) scientist
(b) fusis
(c) fission
(d) fusion
Answer:
(b) fusis

Question 11.
In the measurement of kinetic energy, if the percentage error in mass and speed are 1% and 2% respectively, the maximum percentage error is _______.
(a) 10%
(b) 5%
(c) 3%
(d) 4%
Answer:
(b) 5%

Question 12.
Mass of observable universe …..
(a) 1031 kg
(b) 1041 kg
(c) 1055 kg
(d) 9.11 × 1031 kg
Answer:
(c) 1055 kg

Question 13.
Mass of an electron …….
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 301
Answer:
(b) 9.11 × 10-31 kg

Question 14.
One of the following pairs which do not have identical dimensions is _______.
(a) moment of Inertia & moment of force
(b) work and impulse
(c) angular momentum and planks constant
(d) impulse and momentum
Answer:
(a) moment of Inertia & moment of force

Question 15.
The study of the discrete nature of phenomena at the atomic and subatomic levels.
(a) Quantum mechanics
(b) High energy physics
(c) Acoustics
(d) Classical mechanics
Answer:
(a) Quantum mechanics

Question 16.
The techniQuestion used to study the crystal structure of various rocks are …….
(a) diffraction
(b) interference
(c) total internal reflection
(d) refraction
Answer:
(a) diffraction

Question 17.
A physical quantity is measured and the result is expressed as nu, where u is the unit and n is the numerical value. If the result is expressed in various units then _______.
(a) n ∝ size of u
(b) n ∝ u²
(c) n ∝ \(\sqrt{u}\)
(d) n ∝ l/u
Answer:
(d) n ∝ l/u

Question 18.
The comparison of any physical quantity with its standard unit is known as ……..
(a) fundamental quantities
(b) measurement
(c) dualism
(d) derived quantities
Answer:
(b) measurement

Question 19.
Fundamental quantities can also be known as …… quantities.
(a) original
(b) physical
(c) negative
(d) base
Answer:
(d) base

Question 20.
Choose the wrong option:
(a) A dimensionally correct equation may be correct
(b) A dimensionally correct equation may be incorrect
(c) A dimensionally incorrect equation may be correct
(d) A dimensionally incorrect equation may be incorrect
Answer:
(c) A dimensionally incorrect equation may be correct

Question 21.
The system of the unit not only based on length, mass, and time is
(a) FPS
(b) CGS
(c) MKS
(d) SI
Answer:
(d) SI

Question 22.
The coherent system of units …..
(a) CGS
(b) SI
(c) FPS
(d) MKS
Answer
(b) SI

Question 23.
The function f is given as, f = A sin α + B cos βt where x is the displacement and t is the time. The dimension of is α/β.
(a) [M0L0T0]
(b) [MLT-1]
(c) [M0 L-1 T1]
(d) [M0LT-1]
Answer:
(c) [M0 L-1 T1]

Question 24.
Which of the following is a unit of distance?
(a) Light year
(b) Leap year
(c) Dyne-sec
(d) Pauli
Answer:
(a) Light year

Question 25.
The frequency of vibration of a mass m suspended from a spring of spring constant K givers by a relation of this type, f = Cmxky where c is dimensionless quantity. The value of x and y are:
(a) x = 1/2, y = 1/2
(b) x = – 1/2, y = – 1/2
(c) x = 1/2, y = – 1/2
(d) x = – 1/2, y = 1/2
Answer:
(d) x = – 1/2, y = 1/2

Question 26.
1 radian is ……
(a) 2.91 × 10-4 m
(b) 57.27°
(c) 180°
(d) \(\frac{\pi}{180}\)
Answer:
(b) 57.27°

Question 27.
One degree of arc is …….
(a) 1″
(b) 60″
(c) 60′
(d) 60°
Answer:
(c) 60′

Question 28.
The velocity of water waves v may depend on their wavelength λ the density of water p and the acceleration due to gravity ‘g’, the method of dimensions gives the relation between quantities as _______
(a) v² ∝ λ gρ
(b) γl = \(\frac{p}{2 \ell} \sqrt{\frac{T}{m}} \rho^{-1}\)
(c) v² ∝ g λ
(d) v² ∝ ρ λ
Answer:
(c) v² ∝ g λ

Question 29.
1 minute of arc is equal to …….
(a) 1.745 × 10-2 rad
(b) 2.91 × 10-4 rad
(c) 2.91 × 104 rad
(d) 4.85 × 10-6 rad
Answer:
(b) 2.91 × 10-4 rad

Question 30.
1 second of arc is equal to ………
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 35
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 361

Question 31.
If the time period (T) of vibration of a liquid drop depends on surface tension (s) radius (r) of the drop and density (ρ) of the liquid then the expression of T is _______.
(a) T = k\(\sqrt{\frac{\mathrm{pr}^{3}}{\mathrm{~s}}}\)
(b) T = k\(\sqrt{\frac{\rho^{3} r}{s}}\)
(c) T = k\(\sqrt{\frac{\rho^{3} r}{s^{2}}}\)
(d) none
Answer:
(a) T = k\(\sqrt{\frac{\mathrm{pr}^{3}}{\mathrm{~s}}}\)

Question 32.
Unit of impulse ………..
(a) NS2
(b) NS
(c) Nm
(d) Kgms-2
Answer:
(b) NS

Question 33.
The ratio of energy and temperature is known as ……
(a) Stefen’s constant
(b) Boltzmann constant
(c) Plank’s constant
(d) Kinetic constant
Answer:
(b) Boltzmann constant

Question 34.
In a system of units if force (F) acceleration (a) and time (T) are taken as fundamental units then the dimensional formula for energy is _______.
(a) FA2T
(b) FAT2
(c) F2AT
(d) FAT
Answer:
(a) FA2T

Question 35.
Which of the following is in increased order?
(a) exa, tera, hecto
(b) tera, exa, hecto
(c) giga, tera, exa
(d) hecto, exa, giga
Answer:
(c) giga, tera, exa

Question 36.
10-18 is called as ……
(a) nano
(b) pico
(c) femto
(d) atto
Answer:
(d) atto

Question 37.
A radio signal sent towards the distant planet, returns after “t” s. If “c” is the speed of radio
waves then the distance of the planet and from the earth is …….
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 50
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 51

Question 38.
ML3T-2 θ-1is the dimension of _______
(a) resistivity
(b) conductivity
(c) resistance
(d) none of these
Answer:
(a) resistivity

Question 39.
The shift in the position of an object when viewed with two eyes, keeping one eye closed at a time is known as ………
(a) basis
(b) fundamental
(c) parallax
(d) pendulum
Answer:
(c) parallax

Question 40.
Chandrasekar’s limit is ….. times the mass of the sun.
(a) 1.2
(b) 1.4
(c) 1.6
(d) 1.8
Answer:
(b) 1.4

Question 41.
The respective number of significant figures for the numbers 23.023, 0.0003 and 2.1 x 10-4 are _______
(a) 4, 4, 2
(b) 5, 1, 2
(c) 5, 1, 5
(d) 5, 5, 2
Answer:
(b) 5, 1, 2

Question 42.
Size of the atomic nucleus is …..
(a) 10-10 m
(b) 10-12 m
(c) 10-14 m
(d) 10-18 m
Answer:
(c) 10-14 m

Question 43.
Time interval between two successive heartbeats is in the order of …….
(a) 10° s
(b) 10 s
(c) 102 s
(d) 10-3 s
Answer:
(a) 10° s

Question 44.
A wire has a mass 0.30±.003g radius 0. 5±0.005 mm and length 6±0.06 cm. The maximum percentage error in the measurement of its density is _______
(a) 1%
(b) 2%
(c) 3%
(d) 4%
Answer:
(d) 4%

Question 45.
The uncertainty contained in any measurement is ……
(a) rounding off
(b) error
(c) parallax
(d) gross
Answer:
(b) error

Question 46.
Zero error of an instrument is a ……
(a) Systematic error
(b) Random error
(c) Gross error
(d) Both (a) and (b)
Answer:
(a) Systematic error

Question 47.
Error in the measurement of radius of a sphere is 2%. Then error in the measurement of the surface area is __________________
(a) 1%
(b) 2%
(c) 3%
(d) 4%
Answer:
(d) 4%

Question 48.
The period of oscillation of a simple pendulum is given by T = 2π\(\sqrt{\frac{1}{g}}\) where is about 100 cm and is known to have 1 mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stopwatch of least count 0.1s. The percentage error in g is
(a) 0.1%
(b) 1%
(c) 0.2%
(d) 0.8%
Answer:
(c) 0.2%

Question 49.
Random error can also be called as ……………………..
(a) personal error
(b) chance error
(c) gross error
(d) system error
Answer:
(b) chance error

Question 50.
To get the best possible true value of the quantity has to be taken.
(a) rms value
(b) net value
(c) arithmetic mean
(d) mode
Answer:
(c) arithmetic mean

Question 51.
The density of a solid ball is to be determined in an experiment. The diameter of the ball is measured with a screw gauge whose pitch is 0.5 mm and there are 50 divisions on the circular scale. The reading on the main scale is 2.5 mm and that of the circular scale is 20 divisions. If the measured mass of the ball has a relative error of 2% the relative percentage error in the density is _______.
(a) 0.9%
(b) 2.4%
(c) 3.1%
(d) 4.2%
Answer:
(c) 3.1%

Question 52.
The uncertainty in a measurement is called as ………………….
(a) error
(b) systematic
(c) random error
(d) gross error
Answer:
(a) error

Question 53.
The difference between the true value and the measured value of a quantity is known as …..
(a) Absolute error
(b) Relative error
(c) the Percentage error
(d) Systematic error
Answer:
(a) Absolute error

Question 54.
If a1, a2, a3 …. an are the measured value of a physical quantity “a” and am is the true value then absolute error …..
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 60
Answer:
(d) \(\Delta a_{n}=a_{m}-a_{n}\)

Question 55.
If ‘am‘ and ‘∆am ‘ are true value and mean absolute error respectively, then the magnitude of the quantity may lie between …..
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 61
Answer:
(b) \(a_{m}-\Delta a_{m} \text { to } a_{m}+\Delta a_{m}\)

Question 56.
360° is equal to _______ radian.
(a) π
(b) 2π
(c) π/2
(d) 3π
Answer:
(b) 2π

Question 57.
The relative error can also be called………..
(a) fractional error
(b) absolute error
(c) percentage error
(d) systematic error
Answer:
(a) fractional error

Question 58.
A measured value to be close to the targeted value, percentage error must be close to
(a) 0
(b) 10
(c) 100
(d) ∝
Answer:
(a) 0

Question 59.
1 chandrasekar limit (1CSL) is equal to _______.
(a) 1.6 times the mass of the sun
(b) 2.4 times the mass of the sun
(c) 1.4 times the mass of the sun
(d) 2.6 times the mass of the sun
Answer:
(c) 1.4 times the mass of the sun

Question 60.
The maximum possible error in the difference between the two quantities is ……
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 62
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 63

Question 61.
The maximum fractional error in the division of two quantities is ….
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 64
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 65

Question 62.
The fractional error in the nth power of a quantity is …..
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 66
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 67

Question 63.
A physical quantity is given as y = \(\frac{a b^{3}}{c^{2}}\). If ∆a, ∆b, ∆c are absolute errors, the possible fractional error in y is …..
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 68
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 69

Question 64.
Number of significant digits in 3256 ……..
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(d) 4

Question 65.
Number of significant digits in 32005 ………
(a) 1
(b) 2
(c) 5
(d) 2
Answer:
(c) 5

Question 66.
Number of significant digits in 2030 …
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(d) 4

Question 67.
Number of significant digits in 2030N …..
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(d) 4

Question 68.
Number of significant digits in 0.0342 …..
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(c)3

Question 69.
Number of significant digit in 20.00 …..
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(d) 4

Question 60.
The smallest practical unit of time shakes. 1 shake =_______ seconds.
(a) 10-6
(b) 10-8
(c) 10-12
(d) 10-16
Answer:
(b) 10-8

Question 71.
The force acting on a body is measured as 4.25 N. Round it off with two significant figure ……………
(a) 4.3
(b) 4.2
(c) both
(a) or (b)
(d) 4.25
Answer:
(b) 4.2

Question 72.
The quantities a, b, c are measured as 3.21, 4.253, 7.2346. The sum (a + b + c) with proper significant digits is ……
(a) 14.6976
(b) 14.697
(c) 14.69
(d) 14.6
Answer:
(c) 14.69

Question 73.
The dimensions of gravitational constant G are …
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 80
Answer:
(b) \(\mathbf{M}^{-1} \mathbf{L}^{3} \mathbf{T}^{-2}\)

Question 74.
The ratio of one nanometer to one micron is
(a) 10-3
(b) 103
(c) 10-9
(d) 10-6
Answer:
(b) 103

Question 75.
Which of the following pairs does not have the same dimension?
(a) Moment of inertia and moment of force
(b) Work and torque
(c) Impulse and momentum
(d) Angular momentum and Plank’s constant
Answer:
(a) Moment of inertia and moment of force

Question 76.
Two quantities A and B have different dimensions. Which of the following is physically meaningful?
(a) A + B
(b) A – B
(c) A /B
(d) None
Answer:
(c) A /B

Question 77.
The dimensional formula for the moment of inertia ……
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 81
Answer:
(d) \(\mathbf{M} \mathbf{L}^{2} \mathbf{T}^{\mathbf{0}}\)

Question 78.
Which of the following is having the same dimensional formula?
(a) Work and power
(b) Radius of gyration and displacement
(c) Impulse and force
(d) Frequencies and wavelength
Answer:
(b) Radius of gyration and displacement

Question 79.
Which of the following quantities is expressed as force per unit area?
(a) Pressure
(b) Stress
(c) Both (a) and (b)
(d) None
Answer:
(c) Both (a) and (b)

Question 80.
In the equation of motion Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 85 the dimensional formula for K is ……….
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 86
Answer:
(b) \(\left[\mathbf{L} \mathbf{T}^{-2}\right]\)

Question 81.
The dimensional formula for heat capacity ……
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 87
Answer:
(d) \(\left[\mathbf{M} \mathbf{L}^{2} \mathbf{T}^{2} \mathbf{K}^{-1}\right]\)

Question 82.
The product of Avogadro constant and elementary charge is known as …… constant.
(a) Planck’s
(b) Avagadro
(c) Boltzmann
(d) Faraday
Answer:
(d) Faraday

Question 83.
The force F is given by F = at + bt2 where t is time. The dimensions of ‘a’ and ‘b’ respectively are
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 861
Answer:
(d) \(\left[\mathrm{MLT}^{-2}\right]\) and \(\left[\mathrm{MLT}^{-0}\right]\)

Question 84.
Dimensions of impulse are ………..
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 871
Answer:
(c) \(\left[\mathrm{MLT}^{-1}\right]\)

Question 85.
If the speed of light (c), acceleration due to gravity (g), and pressure (P) are taken as fundamental
units, the possible relation to gravitational constant (G) is …………
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 88
Answer:
(c) \(c^{0} g^{2} p^{-1}\)

Question 86.
The equivalent of one joule is ……….
(a) Nm2
(b) kg m2 s-2
(c) kg m s-1
(d) N kg m2
Answer:
(b) kg m2 s-2

Question 87.
Pick out the dimensionless quantity …..
(a) force
(b) specific gravity
(c) planck’s constant
(d) velocity
Answer:
(b) specific gravity

Question 88.
Odd one out ………
(a) strain
(b) refractive index
(c) numbers
(d) stress
Answer:
(d) stress

Question 89.
A wire has a mass 0.3 ± 0.003g, radius 0.5 ± 0.005 mm and length 6 + 0.06 cm. The maximum percentage error in the measurement of its density is …….
(a) 1%
(b) 2%
(c) 3%
(d) 4%
Answer:
(d) 4%

Question 90.
The dimensions of Planck constant equals that of …..
(a) energy
(b) momentum
(c) angular momentum
(d) power
Answer:
(c) angular momentum

Question 91
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 90
(a) The unit of λ is the same as that of x and A
(b) The unit of λ is the same as that of x but not of A
(c) The unit of c is same as that of 2π/λ
(d) The unit of (ct – x)is same as that 2π/λ
Answer:
(a) The unit of λ is the same as that of x and A

Question 92.
The number of significant figures in 0.06900 is …….
(a) 2
(b) 2
(c) 4
(d) 5
Answer:
(c) 4

Question 93.
The numbers 3.665 and 3.635 on rounding off to 3 significant figures will give
(a) 3.66 and 3.63
(b) 3.66 and 3.64
(c) 3.67 and 3.63
(d) 3.67 and 3.64
Answer:
(b) 3.66 and 3.64

Question 94.
Which of the following measurements is most precise?
(a) 4.00 mm
(b) 4.00 cm
(c) 4.00 m
(d) 4.00 km
Answer:
(a) 4.00 mm

Question 95.
The mean radius of a wire is 2 mm. Which of the following measurements is most accurate? (a) 1.9 mm
(b) 2.25 mm
(c) 2.3 mm
(d) 1.83 mm
Answer:
(a) 1.9 mm

Question 96.
If an error in measurement of the radius of the sphere is 1%. What will be the error in the measurement of volume?
(a) 1%
(b) \(\frac{1}{3}\)%
(c) 3%
(d) 10%
Answer:
(c) 3%

Question 97.
Dimensions [M L-1 T-1] are related to …….
(a) torque
(b) work
(c) energy
(d) Coefficient of viscosity
Answer:
(d) Coefficient of viscosity

Question 98.
The heat produced by a current is obtained a relation H = I2RT. If the errors in measuring these quantities current, resistance, time are 1%, 2%, 1% respectively then the total error in calculating the energy produced is
(a) 2%
(b) 4%
(c) 5%
(d) 6%
Answer:
(c) 5%

Question 99.
Length cannot be measured by ………
(a) fermi
(b) angstrom
(c) parsec
(d) debye
Answer:
(d) debye

Question 100.
The pressure on a square plate is measured by measuring the force on the plate and the length of the sides of the plate by using the formula p = \([/late\frac{\mathrm{F}}{l^{2}}x]. If the maximum errors in the measurement
of force and length are 4% and 2% respectively, then the maximum error in the measurement of pressure is ……..
(a) 1%
(b) 2%
(c) 8%
(d) 10%
Aswer:
(c) 8%

Question 101.
Which of the following cannot be verified by using dimensional analysis?
1 mv2
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 100
Answer:
(b) y = a sin wt

Question 102.
Percentage errors in the measurement of mass and speed are 3% and 2% respectively. The error in the calculation of kinetic energy is …….
(a) 2%
(b) 3%
(c) 5%
(d) 7%
Answer:
(d) 7%

Question 103.
More readings will reduce …….
(a) random error
(b) systematic error
(c) both (a) and (b)
(d) neither (a) nor (b)
Answer:
(a) random error

Question 104.
If the percentage error in the measurement of mass and momentum of a body is 3% and 2% respectively, then the maximum possible error in kinetic energy is
(a) 2%
(b) 3%
(c) 5%
(d) 7%
Answer:
(d) 7%

Question 105.
In a vernier caliper, n divisions of the vernier scale coincide with (n – 1) divisions of the main scale. The least count of the instrument is ………
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 121
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 103

Question 106.
The period of a simple pendulum is recorded as 2.56s, 2.42s, 2.71s, and 2.80s respectively. The average absolute error is
(a) 0.1s
(b) 0.2s
(c) 1.0s
(d) 0.11s
Answer:
(d) 0.11s

Question 107.
In a system of units, if the force (F), acceleration (A), and time (T) are taken as fundamental units then the dimensional formula of energy is
(a) [FA2T]
(b) [FAT2]
(c) [F2AT]
(d) [FAT]
Answer:
(b) [FAT2]

Question 108.
The random error in the arithmetic mean of 50 observations is ‘a’, then the random error in the arithmetic mean of 200 observations a would be
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 104
Answer:
(c) [latex]\frac{a}{4}\)

Question 109.
Which of the following is not dimensionless?
(a) Relative permittivity
(b) Refractive index
(c) Relative density
(d) Relative velocity
Answer:
(d) Relative velocity

Question 110.
If V-velocity, K – kinetic energy, and T – time are chosen as the fundamental units, then what is the dimensional formula for surface tension?
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 110
Answer:
(a) [K V-2 T-2]

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Short Answer Questions (1 Mark)

Question 1.
Write the rules of rounding off with examples.
Answer:
1. If the digit to be dropped is smaller than 5, then the preceding digit should be left unchanged.
Example: 7.32 is rounded off to 7.3

2. If the digit to be dropped is greater than 5 then the preceding digit should be increased by 1.
Example: 8.946 is rounded off to 8.95

3. If the digit to be dropped is 5 followed by digits other than zero, then the preceding digit should be raised by 1.
Example: 1.8159 is rounded off 1.82

4. If is odd and no change if it is even. If followed by zero then the preceding digit should be raised by 1.
Example:
1.8159 is rounded off 1.82
1.8259 is rounded off to 1.82
8.250 is rounded off to 8.2
8.150 is rounded off to 8.2

Question 2.
If x = a + bt + ct2, where x is in metre and t in seconds, what is the unit of c?
Answer:
The unit of the left-hand side is metre so the units of ct2 should also be metre.
Since t2 has unit of s2, so the unit of c is m/s2.

Question 3.
If humans were to settle on other planets which of the fundamental quantities will be in trouble. Why?
Answer:
The fundamental quantities which are in trouble are the quantities which are defined on the basis of vibrating atoms, mostly length.

Question 4.
The radius of atom is of the order of 1 A° & radius of nucleus is of the order of fermi. How many magnitudes higher is the volume of the atom as compared to the volume of nucleus?
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 152

Question 5.
How many kg make 1 unified atomic mass unit?
Answer:
1u = 1.66 × 10-27 kg

Question 6.
Name some physical quantities that have the same dimension.
Answer:
Work, energy, and torque.

Question 7.
Name the physical quantities that have the dimensional formula [ML -1T-2].
Answer:
Stress, pressure, modulus of elasticity.

Question 8.
Give two examples of dimensionless variables.
Answer:
Strain, refractive index.

Question 9.
State the number of significant figures in
(i) 0.007 m2
(ii) 2.64 × 1024 kg
(iii) 0.2370 g cm-3
(iv) 0.2300m
(v) 86400
(vi) 86400 m
Answer:
(i) 1
(ii) 3
(iii) 4
(iv) 4
(v) 3
(vi) 5
since it comes from a measurement the last two zeros become significant.

Question 10.
Given relative error in the measurement of length is 0.02, what is the percentage error?
Answer:
2%.

Question 11.
A physical quantity P is related to four observables a, b, c and d as follows :
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 1101
The percentage errors of measurement in a, b, c, and d are 1%, 3%, 4%, and 2% respectively. What is the percentage error in the quantity P?
Answer:
The relative error in P is given by
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 120

Question 12.
A boy recalls the relation for relativistic mass (m) in terms of rest mass (m0) velocity of particle V but forgets to put the constant c (velocity of light). He writes Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 125 correct the equation by putting the missing ‘c’.
Answer:
Since quantities of similar nature can only be added or subtracted, v2 cannot be subtracted from 1 but v2/c2 can be subtracted from 1.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 1212

Question 13.
Name the technique used in locating
(a) an underwater obstacle
(b) position of an aeroplane in space.
Answer:
(a) SONAR ➝ Sound Navigation and Ranging.
(b) RADAR ➝ Radio Detection and Ranging.

Question 14.
Deduce dimensional formulae of
(i) Boltzmann’s constant
(ii) mechanical equivalent of heat.
Answer:
(i) Boltzmann Constant:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 136

Question 15.
Give examples of dimensional constants and dimensionless constants.
Answer:
Dimensional Constants: Gravitational constant, Plank’s constant. Dimensionless Constants: it, e.

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Short Answer Questions (2 Marks)

Question 16.
The vernier scale of a traveling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm. Calculate the minimum inaccuracy in the measurement of distance.
Answer:
Minimum inaccuracy = Vernier constant
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 137

Question 17.
If the unit of force is 100N, unit of length is 10m and unit of time is 100s. What is the unit of Mass in this system of units ?
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 138

Question 18.
State the principle of homogeneity. Test the dimensional homogeneity of equations
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 139
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 140
as Dimensions of L.H.S. = Dimensions of R.H.S.
∴ The equation to dimensionally homogeneous.

(ii) Sn = Distance travelled in nth sec that is (Sn – Sn – 1)
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 141
Hence this is dimensionally correct.

Question 19.
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 142
Answer:
Since dimensionally similar quantities can only be added
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 143

Question 20.
Magnitude of force experienced by an object moving with speed v is given by F = kv2. Find dimensions of k.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 144

Question 21.
A book with printing error contains four different formulae for displacement. Choose the
correct formula/formulae
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 145
Answer:
The arguments of sine and cosine function must be dimensionless so (a) is the probable correct formulae. Since
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 146

Samacheer Kalvi 11th Physics Nature of Physical World and Measurement Numericals Questions

Question 22.
Determine the number of light-years in one meter.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 240

Question 23.
The mass of a box measured by a grocer’s balance is 2.3 kg. Two gold pieces 20.15 g and 20.17 g are added to the box.
(i) What is the total mass of the box?
(ii) The difference in masses of the pieces to correct significant figures.
Answer:
(i) Mass of box = 2.3 kg
Mass of gold pieces = 20.15 + 20.17 = 40.32 g = 0.04032 kg.
Total mass = 2.3 + 0.04032 = 2.34032 kg
In correct significant figure mass = 2.3 kg (as least decimal)
(ii) Difference in a mass of gold pieces = 0.02 g
In correct significant figure (2 significant fig. minimum decimal) will be 0.02 g.

Question 24.
5.74 g of a substance occupies 1.2 cm3. Express its density to correct significant figures.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 245
Here the least significant figure is 2, so density = 4.8 g/cm3.

Question 25.
If the displacement of a body s = (200 ± 5) m and time is taken by it t = (20 + 0.2) s, then find the percentage error in the calculation of velocity.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 246

Question 26.
If the error in measurement of the mass of a body by 3% and in the measurement of velocity by 2%. What will be the maximum possible error in the calculation of kinetic energy?
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 247

Question 27.
The length of a rod as measured in an experiment was found to be 2.48 m, 2.46 m, 2.49 m, 2.50 m, and 2.48 m. Find the average length, absolute error and percentage error. Express the result with error limit.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 248

Question 28.
A physical quantity is measured as Q = (2.1 ± 0.5) units. Calculate the percentage error in (1) Q2 (2) 2Q.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 249

Question 29.
When the planet Jupiter is at a distance of 824.7 million km from the earth, its angular diameter is measured to be 35.72″ of arc. Calculate the diameter of Jupiter.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 250

Question 30.
A laser light beamed at the moon takes 2.56s and to return after reflection at the moon’s surface. What will be the radius of lunar orbit?
Answer:
t = 2.54 s
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 251

Question 31.
Convert
(i) 3 m.s-2 to km h-2
(ii) G = 6.67 × 10-11 N m2 kg-2 to cm3 g-1 s-2
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 252
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 253

Question 32.
A calorie is a unit of heat or energy and it equals 4.2 J where 1J = 1 kg m2s-2. Suppose we employ a system of units in which unit of mass is α kg, unit of length is β m, unit of time γs. What will be magnitude of calorie in terms of this new system.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 254

Question 33.
The escape velocity v of a body depends on—
(i) the acceleration due to gravity ‘g’ of the planet,
(ii) the radius R of the planet. Establish dimensionally the relation for the escape velocity.
Solution:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 255

Question 34.
The frequency of vibration of a string depends on,
(i) tension in the string
(ii) mass per unit length of string,
(iii) vibrating length of the string. Establish dimensionally the relation for frequency.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 256
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 257

Question 35.
One mole of an ideal gas at STP occupies 22.4 L. What is the ratio of molar volume to atomic volume of a mole of hydrogen? Why is the ratio so large? Take radius of hydrogen molecule to be 1°A.
Answer:
Samacheer Kalvi 11th Physics Solutions Chapter 1 Nature of Physical World and Measurement 258
This ratio is large because actual size of gas molecule is negligible in comparison to the intermolecular separation.

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