Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6

Students can download 12th Business Maths Chapter 4 Differential Equations Ex 4.6 Questions and Answers, Samacheer Kalvi 12th Business Maths Book Solutions Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus and score more marks in your examinations.

Tamilnadu Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6

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Question 1.
The degree of the differential equation \(\frac{d^{4} y}{d x^{4}}-\left(\frac{d^{2} y}{d x^{2}}\right)^{4}+\frac{d y}{d x}=3\) is _________
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(a) 1
Hint:
Since the power of \(\frac{d^{4} y}{d x^{4}}\) is 1

Question 2.
The order and degree of the differential equation \(\sqrt{\frac{d^{2} y}{d x^{2}}}=\sqrt{\frac{d y}{d x}+5}\) are respectively
(a) 2 and 3
(b) 3 and 2
(c) 2 and 1
(d) 2 and 2
Answer:
(c) 2 and 1
Hint:
Squaring both sides, we get \(\frac{d^{2} y}{d x^{2}}=\frac{d y}{d x}+5\)
So order = 2, degree = 1

Question 3.
The order and degree of the differential equation \(\left(\frac{d^{2} y}{d x^{2}}\right)^{\frac{3}{2}}-\sqrt{\left(\frac{d y}{d x}\right)}-4=0\) are respectively.
(a) 2 and 6
(b) 3 and 6
(c) 1 and 4
(d) 2 and 4
Answer:
(a) 2 and 6
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q3

Question 4.
The differential equation \(\left(\frac{d x}{d y}\right)^{3}+2 y^{\frac{1}{2}}=x\) is _________
(a) of order 2 and degree 1
(b) of order 1 and degree 3
(c) of order 1 and degree 6
(d) of order 1 and degree 2
Answer:
(b) of order 1 and degree 3

Question 5.
The differential equation formed by eliminating a and b from y = aex + be-x is _______
(a) \(\frac{d^{2} y}{d x^{2}}-y=0\)
(b) \(\frac{d^{2} y}{d x^{2}}-\frac{d y}{d x}=0\)
(c) \(\frac{d^{2} y}{d x^{2}}=0\)
(d) \(\frac{d^{2} y}{d x^{2}}-x=0\)
Answer:
(a) \(\frac{d^{2} y}{d x^{2}}-y=0\)
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q5

Question 6.
If y = cx + c – c3 then its differential equation is ______
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q6
Answer:
(a) \(y=x \frac{d y}{d x}+\frac{d y}{d x}-\left(\frac{d y}{d x}\right)^{3}\)

Question 7.
The integrating factor of the differential equation \(\frac{d x}{d y}\) + Px = Q is _____
(a) e∫Pdx
(b) ∫Pdx
(c) ∫Pdy
(d) e∫Pdy
Answer:
(d) e∫Pdy

Question 8.
The complementary function of (D2 + 4) y = e2x is _______
(a) (Ax + B) e2x
(b) (Ax + B) e-2x
(c) A cos 2x + B sin 2x
(d) Ax-2x + Be2x
Answer:
(c) A cos 2x + B sin 2x
Hint:
A.E = m2 + 4 = 0 ⇒ m = ±2i
C.F = e0x (A cos 2x + B sin 2x)

Question 9.
The differential equation of y = mx + c is (m and c are arbitrary constants).
(a) \(\frac{d^{2} y}{d x^{2}}=0\)
(b) y = x \(\frac{d y}{d x}\)
(c) x dy + y dx = 0
(d) y dx – x dy = 0
Answer:
(a) \(\frac{d^{2} y}{d x^{2}}=0\)

Question 10.
The particular integral of the differential equation \(\frac{d^{2} y}{d x^{2}}-8 \frac{d y}{d x}+16 y=2 e^{4 x}\) is ________
(a) \(\frac{x^{2} e^{4 x}}{2 !}\)
(b) \(\frac{e^{4 x}}{2 !}\)
(c) x2 e4x
(d) xe4x
Answer:
(c) x2 e4x
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q10

Question 11.
Solution of \(\frac{d x}{d y}\) + px = 0
(a) x = cepy
(b) x = ce-py
(c) x = py + c
(d) x = cy
Answer:
(b) x = ce-py
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q11

Question 12.
If sec2 x is an integrating factor of the differential equation \(\frac{d y}{d x}\) + Py = Q then P = _____
(a) 2 tan x
(b) sec x
(c) cos2 x
(d) tan2 x
Answer:
(a) 2 tan x
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q12

Question 13.
The integrating factor of x\(\frac{d y}{d x}\) – y = x2 is _____
(a) \(\frac{-1}{x}\)
(b) \(\frac{1}{x}\)
(c) log x
(d) x
Answer:
(b) \(\frac{1}{x}\)
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q13

Question 14.
The solution of the differential equation \(\frac{d y}{d x}\) + Py = Q where P and Q are the function of x is ______
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q14
Answer:
(c) \(y e^{\int p d x}=\int \mathrm{Q} e^{\int p d x} d x+c\)

Question 15.
The differential equation formed by eliminating A and B from y = e-2x (A cos x + B sin x) is _______
(a) y2 – 4y1 + 5y = 0
(b) y2 + 4y1 – 5y = 0
(c) y2 – 4y1 – 5y = 0
(d) y2 + 4y1 + 5y = 0
Answer:
(d) y2 + 4y1 + 5y = 0
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q15

Question 16.
The particular integral of the differential equation f(D) y = eax where f(D) = (D – a)2 ________
(a) \(\frac{x^{2}}{2} e^{2 x}\)
(b) xeax
(c) \(\frac{x}{2} e^{2 x}\)
(d) x2 e2x
Answer:
(a) \(\frac{x^{2}}{2} e^{2 x}\)

Question 17.
The differential equation of x2 + y2 = a2 is _____
(a) x dy + y dx = 0
(b) y dx – x dy = 0
(c) x dx – y dx = 0
(d) x dx + y dy = 0
Answer:
(d) x dx + y dy = 0
Hint:
x2 + y2 = a2
⇒ 2x + 2y \(\frac{d y}{d x}\) = 0
⇒ x dx + y dy = 0

Question 18.
The complementary function of \(\frac{d^{2} y}{d x^{2}}-\frac{d y}{d x}=0\) is ______
(a) A + B ex
(b) (A + B) ex
(c) (Ax + B) ex
(d) (Aex + B)
Answer:
(a) A + B ex
Hint:
A.E is m2 – m = 0
⇒ m(m – 1) = 0
⇒ m = 0, 1
CF is Ae0x + Bex = A + Bex

Question 19.
The P.I of (3D2 + D – 14)y = 13e2x is _______
(a) \(\frac{x}{2}\) e2x
(b) x e2x
(c) \(\frac{x^{2}}{2}\) e2x
(d) 13xe2x
Answer:
(b) xe2x
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q19

Question 20.
The general solution of the differential equation \(\frac{d y}{d x}\) = cos x is _______
(a) y = sin x + 1
(b) y = sin x – 2
(c) y = cos x + c, c is an arbitrary constant
(d) y = sin x + c, c is an arbitrary constant
Answer:
(d) y = sin x + c, c is an arbitrary constant

Question 21.
A homogeneous differential equation of the form \(\frac{d y}{d x}=f\left(\frac{y}{x}\right)\) can be solved by making substitution
(a) y = vx
(b) v = yx
(c) x = vy
(d) x = v
Answer:
(a) y = vx

Question 22.
A homogeneous differential equation of the form \(\frac{d x}{d y}=f\left(\frac{x}{y}\right)\) can be solved by making substitution,
(a) x = vy
(b) y = vx
(c) y = v
(d) x = v
Answer:
(a) x = vy

Question 23.
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q23
Answer:
(d) \(\frac{1+v}{2 v^{2}} d v=-\frac{d x}{x}\)
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q23.1

Question 24.
Which of the following is the homogeneous differential equation?
(a) (3x – 5) dx = (4y – 1) dy
(b) xy dx – (x3 + y3) dy = 0
(c) y2 dx + (x2 – xy – y2) dy = 0
(d) (x2 + y) dx = (y2 + x) dy
Answer:
(c) y2 dx + (x2 – xy – y2) dy = 0

Question 25.
The solution of the differential equation \(\frac{d y}{d x}=\frac{y}{x}+\frac{f\left(\frac{y}{x}\right)}{f^{\prime}\left(\frac{y}{x}\right)}\) is ______
(a) f(\(\frac{y}{x}\)) = kx
(b) x f(\(\frac{y}{x}\)) = k
(c) f(\(\frac{y}{x}\)) = ky
(d) y f(\(\frac{y}{x}\)) = k
Answer:
(a) f(\(\frac{y}{x}\)) = kx
Hint:
Samacheer Kalvi 12th Business Maths Solutions Chapter 4 Differential Equations Ex 4.6 Q25