Samacheer Kalvi 9th Maths Solutions Chapter 4 Geometry Ex 4.5

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Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 4 Geometry Ex 4.5

9th Maths Geometry Exercise 4.5 Question 1.
Construct the ∆LMN such that LM = 7.5 cm, MN = 5 cm and LN = 8 cm. Locate its centroid.
Solution:
In ∆LMN
LM = 7.5 cm,
MN = 5 cm,
LN = 8 cm
9th Maths Geometry Exercise 4.5 Samacheer Kalvi
Construction :
Step 1 : Draw ∆LMN with LNM = 8 cm, MN = 5 cm, LM = 7.5 cm
Step 2 : Construct perpendicular bisectors for any two sides (LN and MN) to find the mid points of LM and MN.
Step 3 : Draw the medians LD, ME. Let them meet at G.
Step 4 : G is the centroid of the triangle LMN.

9th Maths Exercise 4.5 Question 2.
Draw and locate the centroid of the triangle ABC where right angle at A, AB = 4 cm and AC = 3 cm.
Solution:
In ∆ABC,
AB = 4 cm,
AC = 3 cm,
∠A = 90°
9th Maths Exercise 4.5 Samacheer Kalvi
Construction:
Step 1 : Draw ∆ABC with AB = 4 cm, AC = 3 cm, ∠A = 90°
Step 2 : Draw perpendicular bisectors of any two sides (AB and AC) to find the mid points of AB and AC.
Step 3 : Draw the medians CD and BE. Let them meet at G.
Step 4 : G is the centroid of the given triangle.

Question 3.
Draw the ∆ABC , where AB = 6 cm, ∠B = 110° and AC = 9 cm and construct the centroid.
Solution:
In ∆ABC,
AB = 6 cm,
∠B = 110°
AC = 9 cm
9th Maths Geometry Samacheer Kalvi
Construction:
Step 1 : Draw ∆ABC with AB = 6 cm, ∠B =110°, AC = 9 cm
Step 2 : Draw perpendicular bisectors of any two sides (BC and AB) to find the mid points of BC and AB.
Step 3 : Construct medians AD and CE. Let them meet at G.
Step 4 : G is the centroid of the given ∆ABC.

9th Maths Geometry Question 4.
Construct the ∆PQR such that PQ = 5 cm, PR = 6 cm and ∠QPR = 60° and locate its centroid.
Solution:
In ∆PQR, PQ = 5 cm, PR = 6 cm, ∠QPR = 60°
9th Standard Maths Exercise 4.5 Samacheer Kalvi
Construction :
Step 1 : Draw ∆PQR with the given measurement
Step 2 : Draw perpendicular bisectors of any two sides (PQ and QR) to find the mid points of PQ and QR.
Step 3 : Draw medians PD and RE. Let them meet at G.
Step 4 : G is the centroid of the given ∆PQR.

9th Standard Maths Exercise 4.5 Question 5.
Draw ∆PQR with sides PQ = 7 cm, QR = 8 cm and PR = 5 cm and construct its Orthocentre.
Solution:
∆PQR with sides PQ = 7 cm,
QR = 8 cm,
PR = 5 cm.
9th Geometry 4.5 Samacheer Kalvi
Construction:
(i) Draw the ∆PQR with the given measurements.
(ii) Construct altitudes from any two vertices (R and P) to their opposite sides (PQ and QR) respectively.
(iii) The point of intersection of the altitude H is the Orthocentre at the given ∆PQR.

9th Geometry 4.5 Question 6.
Draw an equilateral triangle of sides 6.5 cm and locate its Orthocentre.
Samacheer Kalvi 9th Maths Chapter 4 Geometry Ex 4.5 50
Solution:
Equilateral triangle at sides 6.5 cm.
9th Maths Practical Geometry Samacheer Kalvi
Construction :
(i) Draw the ∆ABC with the given measurements.
(ii) Construct altitudes from any two vertices A and B, to their opposite sides BC and AC respectively.
(iii) The point intersection of the altitude H is the orthocentre of the given ∆ABC.

9th Maths Practical Geometry Question 7.
Draw ∆ABC, where AB = 6 cm, ∠B = 110° and BC = 5 cm and construct its Orthocentre.
Solution:
∆ABC, where AB = 6 cm,
B = 110° and
BC = 5 cm.
9th Maths 4.5 Samacheer Kalvi
(i) Draw the ∆ABC with the given measurements.
(ii) Construct altitudes from any two vertices (A and B), to their opposite sides (BC and AC) respectively.
(iii) The point of intersection the altitude H is the orthocentre of the given ∆ABC.

9th Maths 4.5 Question 8.
Draw and locate the Orthocentre of a right triangle PQR where PQ = 4.5 cm, QR = 6 cm and PR = 7.5 cm.
Solution:
Right triangle PQR where PQ = 4.5 cm, QR = 6 cm and PR = 7.5 cm.
9th Maths Geometry Exercise 4.5 Solutions Samacheer Kalvi
Construction:
(i) Draw the ∆PQR with the given measurements.
(ii) Construct altitudes from any two vertices R and Q, to their opposite sides PQ and PR respectively.
(iii) The point of intersection of the altitude H is the orthocentre of the given ∆PQR.